Difference between revisions of "1958 AHSME Problems/Problem 3"
(Added page) |
m (→See also) |
||
| (2 intermediate revisions by 2 users not shown) | |||
| Line 11: | Line 11: | ||
==Solution== | ==Solution== | ||
| − | {{ | + | <math> \frac{a^{-1}b^{-1}}{a^{-3} - b^{-3}} = \frac{\frac{1}{ab}}{\frac{1}{a^{3}}-\frac{1}{b^{3}}} = \frac{\frac{1}{ab}}{\frac{1}{a^{3}}-\frac{1}{b^{3}}}\cdot\frac{a^{3}b^{3}}{a^{3}b^{3}} = \frac{a^{2}b^{2}}{b^{3}-a^{3}}</math>, <math>\boxed{\text{B}}</math>. |
==See also== | ==See also== | ||
| − | {{AHSME box|year=1958|num-b=2|num-a=4}} | + | {{AHSME 50p box|year=1958|num-b=2|num-a=4}} |
| + | {{MAA Notice}} | ||
Latest revision as of 05:10, 3 October 2014
Problem
Of the following expressions the one equal to 
is:
Solution
, 
.
See also
| 1958 AHSC (Problems • Answer Key • Resources) | ||
| Preceded by Problem 2 |
Followed by Problem 4 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 • 31 • 32 • 33 • 34 • 35 • 36 • 37 • 38 • 39 • 40 • 41 • 42 • 43 • 44 • 45 • 46 • 47 • 48 • 49 • 50 | ||
| All AHSME Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
