Difference between revisions of "1958 AHSME Problems/Problem 6"
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==Solution== | ==Solution== | ||
| − | + | We have <math> \frac{1}{2}\cdot \left(\frac{x + a}{x} + \frac{x - a}{x}\right) = \frac{2}{2} = \boxed{\text{(B) }{1}}</math>. | |
| − | {{ | ||
==See also== | ==See also== | ||
| − | {{AHSME box|year=1958|num-b=5|num-a=7}} | + | {{AHSME 50p box|year=1958|num-b=5|num-a=7}} |
| + | {{MAA Notice}} | ||
Latest revision as of 05:09, 3 October 2014
Problem
The arithmetic mean between 
and 
, when 
, is:
Solution
We have 
.
See also
| 1958 AHSC (Problems • Answer Key • Resources) | ||
| Preceded by Problem 5 |
Followed by Problem 7 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 • 31 • 32 • 33 • 34 • 35 • 36 • 37 • 38 • 39 • 40 • 41 • 42 • 43 • 44 • 45 • 46 • 47 • 48 • 49 • 50 | ||
| All AHSME Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
