Difference between revisions of "1993 AJHSME Problems/Problem 4"
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| − | == Problem | + | == Problem == |
<math>1000\times 1993 \times 0.1993 \times 10 = </math> | <math>1000\times 1993 \times 0.1993 \times 10 = </math> | ||
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==Solution== | ==Solution== | ||
| − | <math>1000\times10=10^4</math> | + | <math>1000\times10=10^4\\ |
| + | 0.1993=1993\times10^{-4}\\ | ||
| + | 1993\times1993\times10^{-4}\times10^4= \boxed{\textbf{(E)}\ (1993)^2}</math> | ||
| − | + | ==See Also== | |
| − | + | {{AJHSME box|year=1993|num-b=3|num-a=5}} | |
| − | + | {{MAA Notice}} | |
| − | |||
Latest revision as of 23:10, 4 July 2013
Problem
Solution
See Also
| 1993 AJHSME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 3 |
Followed by Problem 5 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
