Difference between revisions of "2011 AMC 8 Problems/Problem 20"
(→Video Solution by SpreadTheMathLove) |
|||
(10 intermediate revisions by 6 users not shown) | |||
Line 62: | Line 62: | ||
<cmath>12\cdot \frac{(50+75)}{2} = 6(125) = \boxed{\textbf{(D)}\ 750}</cmath> | <cmath>12\cdot \frac{(50+75)}{2} = 6(125) = \boxed{\textbf{(D)}\ 750}</cmath> | ||
+ | |||
+ | == Video Solution by OmegaLearn == | ||
+ | https://youtu.be/51K3uCzntWs?t=2521 | ||
+ | |||
+ | ~ pi_is_3.14 | ||
+ | |||
+ | ==Video Solution by WhyMath== | ||
+ | https://youtu.be/MjxiQ9MZiHk | ||
+ | |||
+ | ~savannahsolver | ||
==See Also== | ==See Also== | ||
{{AMC8 box|year=2011|num-b=19|num-a=21}} | {{AMC8 box|year=2011|num-b=19|num-a=21}} | ||
{{MAA Notice}} | {{MAA Notice}} |
Latest revision as of 11:31, 15 July 2024
Problem
Quadrilateral is a trapezoid,
,
,
, and the altitude is
. What is the area of the trapezoid?
Solution
If you draw altitudes from and
to
the trapezoid will be divided into two right triangles and a rectangle. You can find the values of
and
with the Pythagorean theorem.
is a rectangle so
The area of the trapezoid is
Video Solution by OmegaLearn
https://youtu.be/51K3uCzntWs?t=2521
~ pi_is_3.14
Video Solution by WhyMath
~savannahsolver
See Also
2011 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 19 |
Followed by Problem 21 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.