Difference between revisions of "2007 AMC 12A Problems/Problem 5"

m (Problem)
(Solution 2)
 
(16 intermediate revisions by 5 users not shown)
Line 1: Line 1:
 
{{duplicate|[[2007 AMC 12A Problems|2007 AMC 12A #5]] and [[2007 AMC 10A Problems/Problem 7|2007 AMC 10A #7]]}}
 
{{duplicate|[[2007 AMC 12A Problems|2007 AMC 12A #5]] and [[2007 AMC 10A Problems/Problem 7|2007 AMC 10A #7]]}}
 
==Problem==
 
==Problem==
Last year he paid <math>20\%</math> in federal taxes on his income, and paid <math>10\%</math> of what he had left to pay for state taxes. He paid a total of <math>\textdollar10500</math> for both expenses. How many dollars did he get from the beginning?
+
Last year Mr. Jon Q. Public received an inheritance. He paid <math>20\%</math> in federal taxes on the inheritance, and paid <math>10\%</math> of what he had left in state taxes. He paid a total of <math>\textdollar10500</math> for both taxes. How many dollars was his inheritance?
  
 
<math>(\mathrm {A})\ 30000 \qquad (\mathrm {B})\ 32500 \qquad(\mathrm {C})\ 35000 \qquad(\mathrm {D})\ 37500 \qquad(\mathrm {E})\ 40000</math>
 
<math>(\mathrm {A})\ 30000 \qquad (\mathrm {B})\ 32500 \qquad(\mathrm {C})\ 35000 \qquad(\mathrm {D})\ 37500 \qquad(\mathrm {E})\ 40000</math>
  
==HCR solution==
+
==Solution 1==
 
After paying his taxes, he has <math>0.8*0.9=0.72</math> of his earnings left. Since <math>10500</math> is <math>0.28</math> of his income, he got a total of <math>\frac{10500}{0.28}=37500\  \mathrm{(D)}</math>.
 
After paying his taxes, he has <math>0.8*0.9=0.72</math> of his earnings left. Since <math>10500</math> is <math>0.28</math> of his income, he got a total of <math>\frac{10500}{0.28}=37500\  \mathrm{(D)}</math>.
 +
== Solution 2 ==
 +
Let his total inheritance be a number <math>x</math>. The amount of tax he has to pay at first can be represented as <math>0.2x</math>. The amount of money he has left over after this expense can be written as <math>0.8x</math>. He then has to pay <math>10\%</math> tax on this remaining amount, which can be written as <math>0.1(0.8x) = 0.08x</math>. The combined expense of these taxes is <math>10500</math>, so <math>0.2x + 0.08x = 10500 \Longrightarrow 0.28x = 10500</math>. Therefore <math>x = \frac{10500}{0.28}\ = 37500  \mathrm{(D)}</math>. [[User:Ankitamc|Ankitamc]] ([[User talk:Ankitamc|talk]]) 13:32, 17 January 2021 (EST)AnkitAmc.
 +
~edited by mobius247
  
 
==See also==
 
==See also==

Latest revision as of 11:27, 3 June 2021

The following problem is from both the 2007 AMC 12A #5 and 2007 AMC 10A #7, so both problems redirect to this page.

Problem

Last year Mr. Jon Q. Public received an inheritance. He paid $20\%$ in federal taxes on the inheritance, and paid $10\%$ of what he had left in state taxes. He paid a total of $\textdollar10500$ for both taxes. How many dollars was his inheritance?

$(\mathrm {A})\ 30000 \qquad (\mathrm {B})\ 32500 \qquad(\mathrm {C})\ 35000 \qquad(\mathrm {D})\ 37500 \qquad(\mathrm {E})\ 40000$

Solution 1

After paying his taxes, he has $0.8*0.9=0.72$ of his earnings left. Since $10500$ is $0.28$ of his income, he got a total of $\frac{10500}{0.28}=37500\  \mathrm{(D)}$.

Solution 2

Let his total inheritance be a number $x$. The amount of tax he has to pay at first can be represented as $0.2x$. The amount of money he has left over after this expense can be written as $0.8x$. He then has to pay $10\%$ tax on this remaining amount, which can be written as $0.1(0.8x) = 0.08x$. The combined expense of these taxes is $10500$, so $0.2x + 0.08x = 10500 \Longrightarrow 0.28x = 10500$. Therefore $x = \frac{10500}{0.28}\ = 37500  \mathrm{(D)}$. Ankitamc (talk) 13:32, 17 January 2021 (EST)AnkitAmc. ~edited by mobius247

See also

2007 AMC 12A (ProblemsAnswer KeyResources)
Preceded by
Problem 4
Followed by
Problem 6
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 12 Problems and Solutions
2007 AMC 10A (ProblemsAnswer KeyResources)
Preceded by
Problem 6
Followed by
Problem 8
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 10 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png