Difference between revisions of "1952 AHSME Problems/Problem 32"

Latest revision as of 21:22, 12 April 2020

Problem

$K$ takes $30$ minutes less time than $M$ to travel a distance of $30$ miles. $K$ travels $\frac {1}{3}$ mile per hour faster than $M$ . If $x$ is $K$ 's rate of speed in miles per hours, then $K$ 's time for the distance is:

$\textbf{(A)}\ \dfrac{x + \frac {1}{3}}{30} \qquad \textbf{(B)}\ \dfrac{x - \frac {1}{3}}{30} \qquad \textbf{(C)}\ \frac{30}{x+\frac{1}{3}}\qquad \textbf{(D)}\ \frac{30}{x}\qquad \textbf{(E)}\ \frac{x}{30}$

Solution

Using the formula d=rt, and setting d=30 and r=x, we can easily see that the answer is $\fbox{D}$ . Note that the first sentence is irrelevant.

1952 AHSC (Problems • Answer Key • Resources)
Preceded by Problem 31	Followed by Problem 33
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All AHSME Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.

@@ Line 10: / Line 10: @@
 == Solution ==
-<math>\fbox{D}</math>
+Using the formula d=rt, and setting d=30 and r=x, we can easily see that the answer is <math>\fbox{D}</math>.
+Note that the first sentence is irrelevant.
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Difference between revisions of "1952 AHSME Problems/Problem 32"

Latest revision as of 21:22, 12 April 2020

Problem

Solution

See also