Difference between revisions of "2006 iTest Problems/Problem 1"
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− | A [[divisor]] could include or exclude 2, include or exclude 17, and include or exclude 59. Thus, there are <math>2^3 = \boxed{\textbf{(A)} 8}</math> positive integral divisors. We can also note that answer choice A is the only answer choice and simply selected the option from the start. | + | A [[divisor]] could include or exclude 2, include or exclude 17, and include or exclude 59. Thus, there are <math>2^3 = \boxed{\textbf{(A) } 8}</math> positive integral divisors. We can also note that answer choice A is the only answer choice and simply selected the option from the start. |
+ | |||
+ | ==Obvious Solution== | ||
+ | Since there is only one answer choice, the answer is <math>\boxed{\textbf{(A)}~8}.</math> | ||
==See Also== | ==See Also== | ||
− | + | {{iTest box|year=2006|before=First Problem|num-a=2|ver=[[2006 iTest Problems/Problem U1|U1]] '''•''' [[2006 iTest Problems/Problem U2|U2]] '''•''' [[2006 iTest Problems/Problem U3|U3]] '''•''' [[2006 iTest Problems/Problem U4|U4]] '''•''' [[2006 iTest Problems/Problem U5|U5]] '''•''' [[2006 iTest Problems/Problem U6|U6]] '''•''' [[2006 iTest Problems/Problem U7|U7]] '''•''' [[2006 iTest Problems/Problem U8|U8]] '''•''' [[2006 iTest Problems/Problem U9|U9]] '''•''' [[2006 iTest Problems/Problem U10|U10]]}} | |
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− | [[Category:Introductory | + | [[Category:Introductory Number Theory Problems]] |
Latest revision as of 23:08, 7 June 2021
Contents
Problem
Find the number of positive integral divisors of 2006.
Solution
First, factor the number 2006.
A divisor could include or exclude 2, include or exclude 17, and include or exclude 59. Thus, there are positive integral divisors. We can also note that answer choice A is the only answer choice and simply selected the option from the start.
Obvious Solution
Since there is only one answer choice, the answer is
See Also
2006 iTest (Problems, Answer Key) | ||
Preceded by: First Problem |
Followed by: Problem 2 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 • 31 • 32 • 33 • 34 • 35 • 36 • 37 • 38 • 39 • 40 • U1 • U2 • U3 • U4 • U5 • U6 • U7 • U8 • U9 • U10 |