Difference between revisions of "1964 AHSME Problems/Problem 38"
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− | <cmath>QR=9=\boxed{}</cmath> | + | <cmath>QR=9=\boxed{D}</cmath> |
==See Also== | ==See Also== |
Revision as of 17:17, 9 March 2020
Problem
The sides and of triangle are respectively of lengths inches, and inches. The median is inches. Then , in inches, is:
Solution
By the Median Formula,
Plugging in the numbers given in the problem, we get
Solving,
See Also
1964 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 37 |
Followed by Problem 39 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 • 31 • 32 • 33 • 34 • 35 • 36 • 37 • 38 • 39 • 40 | ||
All AHSME Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.