Difference between revisions of "2017 AMC 8 Problems/Problem 1"
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==Solution 1== | ==Solution 1== | ||
| − | We will compute each expression. A) <math>2+0+1+7=10</math>. B) <math>2 \times 0+1+7=8</math> C) <math>2+0\times 1+7=9</math> D) <math>2+0+1\times 7=9</math>. E)<math>2\times 0\times 1 \times 7 =0</math> Ordering these we get <math>10,8,9,9,0</math> Out of these <math>10</math> is the largest number. Option <math>(A)</math> adds up to ten. Therefore, the answer is <math>\boxed{(A)}</math>- | + | We will compute each expression. A) <math>2+0+1+7=10</math>. B) <math>2 \times 0+1+7=8</math> C) <math>2+0\times 1+7=9</math> D) <math>2+0+1\times 7=9</math>. E)<math>2\times 0\times 1 \times 7 =0</math> Ordering these we get <math>10,8,9,9,0</math> Out of these <math>10</math> is the largest number. Option <math>(A)</math> adds up to ten. Therefore, the answer is <math>\boxed{(A) 2+0+1+7}</math>- SBose |
==Solution 2== | ==Solution 2== | ||
Revision as of 18:28, 12 November 2020
Problem 1
Which of the following values is largest?
Solution 1
We will compute each expression. A) 
. B) 
C) 
D) 
. E)
Ordering these we get 
Out of these 
is the largest number. Option 
adds up to ten. Therefore, the answer is 
- SBose
Solution 2
We immediately see that every one of the choices, except for A and D, has a number multiplied by 
. This will only make the expression's value smaller. We are left with A and D, but in D, 
is multiplied by 
to get , whereas in answer choice A, we get 
out of and , instead of . Therefore, is your answer.
Video Solution
See Also
| 2017 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by First Problem |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
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