Difference between revisions of "2021 AIME II Problems/Problem 10"
Arcticturn (talk | contribs) (→Solution) |
Arcticturn (talk | contribs) (→Solution) |
||
| Line 2: | Line 2: | ||
Two spheres with radii <math>36</math> and one sphere with radius <math>13</math> are each externally tangent to the other two spheres and to two different planes <math>\mathcal{P}</math> and <math>\mathcal{Q}</math>. The intersection of planes <math>\mathcal{P}</math> and <math>\mathcal{Q}</math> is the line <math>\ell</math>. The distance from line <math>\ell</math> to the point where the sphere with radius <math>13</math> is tangent to plane <math>\mathcal{P}</math> is <math>\tfrac{m}{n}</math>, where <math>m</math> and <math>n</math> are relatively prime positive integers. Find <math>m + n</math>. | Two spheres with radii <math>36</math> and one sphere with radius <math>13</math> are each externally tangent to the other two spheres and to two different planes <math>\mathcal{P}</math> and <math>\mathcal{Q}</math>. The intersection of planes <math>\mathcal{P}</math> and <math>\mathcal{Q}</math> is the line <math>\ell</math>. The distance from line <math>\ell</math> to the point where the sphere with radius <math>13</math> is tangent to plane <math>\mathcal{P}</math> is <math>\tfrac{m}{n}</math>, where <math>m</math> and <math>n</math> are relatively prime positive integers. Find <math>m + n</math>. | ||
| − | ==Solution== | + | ==Solution 1== |
The centers of the three spheres form a 49-49-72 triangle. Consider the points at which the plane is tangent to the two bigger spheres; the line segment connecting these two points should be parallel to the 72 side of this triangle. Take its midpoint <math>M</math>, which is 36 away from the midpoint of the 72 side <math>A</math>, and connect these two midpoints. | The centers of the three spheres form a 49-49-72 triangle. Consider the points at which the plane is tangent to the two bigger spheres; the line segment connecting these two points should be parallel to the 72 side of this triangle. Take its midpoint <math>M</math>, which is 36 away from the midpoint of the 72 side <math>A</math>, and connect these two midpoints. | ||
| Line 12: | Line 12: | ||
-Ross Gao | -Ross Gao | ||
| − | + | ==Solution 2== | |
==See also== | ==See also== | ||
{{AIME box|year=2021|n=II|num-b=9|num-a=11}} | {{AIME box|year=2021|n=II|num-b=9|num-a=11}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 16:23, 28 March 2021
Contents
Problem
Two spheres with radii 
and one sphere with radius 
are each externally tangent to the other two spheres and to two different planes 
and 
. The intersection of planes and is the line 
. The distance from line to the point where the sphere with radius is tangent to plane is 
, where 
and 
are relatively prime positive integers. Find 
.
Solution 1
The centers of the three spheres form a 49-49-72 triangle. Consider the points at which the plane is tangent to the two bigger spheres; the line segment connecting these two points should be parallel to the 72 side of this triangle. Take its midpoint 
, which is 36 away from the midpoint of the 72 side 
, and connect these two midpoints.
Now consider the point at which the plane is tangent to the small sphere, and connect with the small sphere's tangent point 
. Extend 
through B until it hits the ray from through the center of the small sphere (convince yourself that these two intersect). Call this intersection 
, the center of the small sphere 
, we want to find 
.
By Pythagorus AC= 
, and we know 
. We know that 
must be parallel, using ratios we realize that 
. Apply Pythagorean theorem on triangle BCD; 
, so 312 + 23 = 
-Ross Gao
Solution 2
See also
| 2021 AIME II (Problems • Answer Key • Resources) | ||
| Preceded by Problem 9 |
Followed by Problem 11 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 | ||
| All AIME Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
