Difference between revisions of "1980 AHSME Problems/Problem 18"
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Line 14: | Line 14: | ||
<cmath>b^{2c}+b^{2a}=1</cmath> | <cmath>b^{2c}+b^{2a}=1</cmath> | ||
<cmath>b^{2c}=1-b^{2a}</cmath> | <cmath>b^{2c}=1-b^{2a}</cmath> | ||
− | <cmath>\log_b 1-b^{2a} = 2c</cmath> | + | <cmath>\log_b (1-b^{2a}) = 2c</cmath> |
<cmath>c=\boxed{\text{(D)} \ \frac 12 \log_b(1-b^{2a})}</cmath> | <cmath>c=\boxed{\text{(D)} \ \frac 12 \log_b(1-b^{2a})}</cmath> | ||
Latest revision as of 19:45, 18 June 2021
Problem
If , , , and , then equals
Solution
Since ,
-aopspandy
See also
1980 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 17 |
Followed by Problem 19 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
All AHSME Problems and Solutions |
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