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Difference between revisions of "2021 Fall AMC 12B Problems/Problem 6"

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~Steven Chen (www.professorchenedu.com) ~NH14 ~kingofpineapplz ~Arcticturn
 
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==Video Solution by Interstigation==
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===Video Solution 1==
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~Education, the Study of Everything
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=Video Solution by Interstigation==
 
https://youtu.be/p9_RH4s-kBA?t=1121
 
https://youtu.be/p9_RH4s-kBA?t=1121
  

Revision as of 14:31, 16 August 2022

The following problem is from both the 2021 Fall AMC 10B #8 and 2021 Fall AMC 12B #6, so both problems redirect to this page.

Problem

The largest prime factor of $16384$ is $2$ because $16384 = 2^{14}$. What is the sum of the digits of the greatest prime number that is a divisor of $16383$?

$\textbf{(A)} \: 3\qquad\textbf{(B)} \: 7\qquad\textbf{(C)} \: 10\qquad\textbf{(D)} \: 16\qquad\textbf{(E)} \: 22$

Solution

We have \begin{align*} 16383 & = 2^{14} - 1 \\ & = \left( 2^7 + 1 \right) \left( 2^7 - 1 \right) \\ & = 129 \cdot 127 \\ & = 3 \cdot 43 \cdot 127. \end{align*}

Therefore, the greatest prime divisor of $16383$ is $127.$ The sum of its digits is $1+2+7=\boxed{\textbf{(C)} \: 10}.$

~Steven Chen (www.professorchenedu.com) ~NH14 ~kingofpineapplz ~Arcticturn

=Video Solution 1

https://youtu.be/NB6CamKgDaw

~Education, the Study of Everything



Video Solution by Interstigation=

https://youtu.be/p9_RH4s-kBA?t=1121

See Also

2021 Fall AMC 10B (Problems • Answer Key • Resources)
Preceded by
Problem 7 		Followed by
Problem 9
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AMC 10 Problems and Solutions
2021 Fall AMC 12B (Problems • Answer Key • Resources)
Preceded by
Problem 5 		Followed by
Problem 7
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AMC 12 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png

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