Difference between revisions of "2023 AMC 10A Problems/Problem 5"
(→Solution 1) |
m (→Problem: Remove center align) |
||
| Line 2: | Line 2: | ||
How many digits are in the base-ten representation of <math>8^5 \cdot 5^{10} \cdot 15^5</math>? | How many digits are in the base-ten representation of <math>8^5 \cdot 5^{10} \cdot 15^5</math>? | ||
| − | < | + | <math>\textbf{(A)}~14\qquad\textbf{(B)}~15\qquad\textbf{(C)}~16\qquad\textbf{(D)}~17\qquad\textbf{(E)}~18\qquad</math> |
==Solution 1== | ==Solution 1== | ||
Revision as of 20:57, 9 November 2023
Problem
How many digits are in the base-ten representation of 
?
Solution 1
Prime factorization of this gives us 
. Pairing 
and 
together gives us a number with 
zeros, or 15 digits. 
and this adds an extra 3 digits. 
~zhenghua
See Also
| 2023 AMC 12A (Problems • Answer Key • Resources) | |
| Preceded by Problem 3 |
Followed by Problem 5 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
| 2023 AMC 10A (Problems • Answer Key • Resources) | ||
| Preceded by Problem 4 |
Followed by Problem 6 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
