Difference between revisions of "1992 AJHSME Problems/Problem 24"
Mrdavid445 (talk | contribs) (Created page with "==Problem== Four circles of radius <math>3</math> are arranged as shown. Their centers are the vertices of a square. The area of the shaded region is closest to <asy> fill((3...") |
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<math>\text{(A)}\ 7.7 \qquad \text{(B)}\ 12.1 \qquad \text{(C)}\ 17.2 \qquad \text{(D)}\ 18 \qquad \text{(E)}\ 27</math> | <math>\text{(A)}\ 7.7 \qquad \text{(B)}\ 12.1 \qquad \text{(C)}\ 17.2 \qquad \text{(D)}\ 18 \qquad \text{(E)}\ 27</math> | ||
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+ | ==Solution== | ||
+ | The side of the square of made up of two radii, and the area of the square is <math>(3+3)^2=36</math>. The unshaded region of the square is composed of four quarter circles, and has the area of one circle, which is <math>9\pi</math>. The area of the shaded region is <math>36-9\pi</math> which less than <math>36-9(3)=9</math>, closest to <math>\boxed{\text{(A)}\ 7.7}</math>. | ||
+ | |||
+ | ==See Also== | ||
+ | {{AJHSME box|year=1992|num-b=23|num-a=25}} |
Revision as of 21:17, 22 December 2012
Problem
Four circles of radius are arranged as shown. Their centers are the vertices of a square. The area of the shaded region is closest to
Solution
The side of the square of made up of two radii, and the area of the square is . The unshaded region of the square is composed of four quarter circles, and has the area of one circle, which is . The area of the shaded region is which less than , closest to .
See Also
1992 AJHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 23 |
Followed by Problem 25 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |