Difference between revisions of "2002 AMC 12B Problems/Problem 23"
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[[Category:Introductory Geometry Problems]] | [[Category:Introductory Geometry Problems]] | ||
+ | [[http://baovevn.vn/cong-ty-tu-van-nghiep-vu-bao-ve/ cong ty bao ve]] | ||
+ | [[http://www.cuudulieu24h.com cuu du lieu]] | ||
+ | [[http://noithathoangduy.com.vn noithat]] | ||
+ | [[http://ihrp.fis.com.vn/ Phần mềm nhân sự]] | ||
+ | [[http://ihrp.fis.com.vn/ Quản lý Nhân sự]] | ||
+ | [[http://ihrp.fis.com.vn/ Phần mềm quản lý nhân sự tiền lương]] | ||
+ | [[http://thamtuthanglong.com/ tham tu]] | ||
+ | [[http://thamtuthanglong.com/ cong ty tham tu]] | ||
+ | [[http://uvc-thanhlapcongty.com/dang-ky-online/dang-ky-thanh-lap-doanh-nghiep.html thành lập doanh nghiệp]] | ||
+ | [[http://uvc-thanhlapcongty.com/cung-cap-dich-vu/dich-vu-ke-toan.html dịch vụ kế toán]] | ||
+ | [[http://uvc-thanhlapcongty.com/cung-cap-dich-vu/dich-vu-ke-toan.html dich vu ke toan]] | ||
+ | [[http://www.chiemhoa.vn/ ke sieu thi]] | ||
+ | [[http://www.chiemhoa.vn/ quay ke]] |
Revision as of 20:54, 18 January 2012
Problem
In , we have and . Side and the median from to have the same length. What is ?
Solution
Let be the foot of the median from to , and we let . Then by the Law of Cosines on , we have
Since , we can add these two equations and get
Hence and .
Alternate Solution
From Stewart's Theorem, we have Simplifying, we get
See also
2002 AMC 12B (Problems • Answer Key • Resources) | |
Preceded by Problem 22 |
Followed by Problem 24 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All AMC 12 Problems and Solutions |
[cong ty bao ve] [cuu du lieu] [noithat] [Phần mềm nhân sự] [Quản lý Nhân sự] [Phần mềm quản lý nhân sự tiền lương] [tham tu] [cong ty tham tu] [thành lập doanh nghiệp] [dịch vụ kế toán] [dich vu ke toan] [ke sieu thi] [quay ke]