Difference between revisions of "2002 AMC 12B Problems/Problem 23"
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Revision as of 16:03, 19 January 2012
Problem
In , we have
and
. Side
and the median from
to
have the same length. What is
?
Solution
Let be the foot of the median from
to
, and we let
. Then by the Law of Cosines on
, we have
Since , we can add these two equations and get
Hence and
.
Alternate Solution
From Stewart's Theorem, we have Simplifying, we get
See also
2002 AMC 12B (Problems • Answer Key • Resources) | |
Preceded by Problem 22 |
Followed by Problem 24 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All AMC 12 Problems and Solutions |