Difference between revisions of "2012 AMC 8 Problems/Problem 1"
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<math>\textbf{(A)}\hspace{.05in}6 \qquad \textbf{(B)}\hspace{.05in}6\dfrac23 \qquad \textbf{(C)}\hspace{.05in}7\dfrac12 \qquad \textbf{(D)}\hspace{.05in}8 \qquad \textbf{(E)}\hspace{.05in}9 </math> | <math>\textbf{(A)}\hspace{.05in}6 \qquad \textbf{(B)}\hspace{.05in}6\dfrac23 \qquad \textbf{(C)}\hspace{.05in}7\dfrac12 \qquad \textbf{(D)}\hspace{.05in}8 \qquad \textbf{(E)}\hspace{.05in}9 </math> | ||
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+ | ==Solution== | ||
+ | Since Rachelle uses 3 pounds of meat to make 8 hamburgers, she uses <math>\frac{3}{8}</math> pounds of meat to make one hamburger. To find out the pounds of meat she needs for 24 hamburgers, multiply <math>\frac{3}{8}</math> and 24 to obtain the answer, <math>\boxed{\textbf{(E)}\ 9}</math>. | ||
==See Also== | ==See Also== | ||
{{AMC8 box|year=2012|before=First Problem|num-a=2}} | {{AMC8 box|year=2012|before=First Problem|num-a=2}} |
Revision as of 09:38, 24 November 2012
Rachelle uses 3 pounds of meat to make 8 hamburgers for her family. How many pounds of meat does she need to make 24 hamburgers for a neighborhood picnic?
Solution
Since Rachelle uses 3 pounds of meat to make 8 hamburgers, she uses pounds of meat to make one hamburger. To find out the pounds of meat she needs for 24 hamburgers, multiply and 24 to obtain the answer, .
See Also
2012 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by First Problem |
Followed by Problem 2 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |