Difference between revisions of "2012 AMC 8 Problems/Problem 1"
Bharatputra (talk | contribs) |
Bharatputra (talk | contribs) (→Solution) |
||
| Line 4: | Line 4: | ||
==Solution== | ==Solution== | ||
| − | Since Rachelle uses 3 pounds of meat to make 8 hamburgers, she uses <math>\frac{3}{8}</math> pounds of meat to make one hamburger. To find out the pounds of meat she needs for 24 hamburgers, multiply <math>\frac{3}{8}</math> and 24 to obtain the answer, <math>\boxed{\textbf{(E)}\ 9}</math>. | + | Since Rachelle uses <math>3</math> pounds of meat to make <math>8</math> hamburgers, she uses <math>\frac{3}{8}</math> pounds of meat to make one hamburger. To find out the pounds of meat she needs for <math>24</math> hamburgers, multiply <math>\frac{3}{8}</math> and <math>24</math> to obtain the answer, <math>\boxed{\textbf{(E)}\ 9}</math>. |
==See Also== | ==See Also== | ||
{{AMC8 box|year=2012|before=First Problem|num-a=2}} | {{AMC8 box|year=2012|before=First Problem|num-a=2}} | ||
Revision as of 09:45, 24 November 2012
Rachelle uses 3 pounds of meat to make 8 hamburgers for her family. How many pounds of meat does she need to make 24 hamburgers for a neighborhood picnic?
Solution
Since Rachelle uses 
pounds of meat to make 
hamburgers, she uses 
pounds of meat to make one hamburger. To find out the pounds of meat she needs for 
hamburgers, multiply and to obtain the answer, 
.
See Also
| 2012 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by First Problem |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
