Difference between revisions of "1964 AHSME Problems/Problem 29"
(Created page with "==Problem== In this figure <math>\angle RFS=\angle FDR</math>, <math>FD=4</math> inches, <math>DR=6</math> inches, <math>FR=5</math> inches, <math>FS=7\dfrac{1}{2}</math> inches...") |
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==Problem== | ==Problem== | ||
− | In this figure <math>\angle RFS=\angle FDR</math>, <math>FD=4</math> inches, <math>DR=6</math> inches, <math>FR=5</math> inches, <math>FS=7\dfrac{1}{2}</math> inches. The | + | In this figure <math>\angle RFS=\angle FDR</math>, <math>FD=4</math> inches, <math>DR=6</math> inches, <math>FR=5</math> inches, <math>FS=7\dfrac{1}{2}</math> inches. The length of <math>RS</math>, in inches, is: |
<math>\textbf{(A) }\text{undetermined}\qquad\textbf{(B) }4\qquad\textbf{(C) }5\dfrac{1}{2}\qquad\textbf{(D) }6\qquad\textbf{(E) }6\dfrac{1}{2}\qquad</math> | <math>\textbf{(A) }\text{undetermined}\qquad\textbf{(B) }4\qquad\textbf{(C) }5\dfrac{1}{2}\qquad\textbf{(D) }6\qquad\textbf{(E) }6\dfrac{1}{2}\qquad</math> | ||
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label("$7\frac{1}{2}$",3.75,dir(-90)); | label("$7\frac{1}{2}$",3.75,dir(-90)); | ||
</asy> | </asy> | ||
+ | |||
+ | ==See Also== | ||
+ | {{AHSME 40p box|year=1964|num-b=28|num-a=30}} | ||
+ | |||
+ | [[Category:Introductory Geometry Problems]] | ||
+ | |||
+ | {{MAA Notice}} |
Revision as of 22:14, 24 July 2019
Problem
In this figure , inches, inches, inches, inches. The length of , in inches, is:
See Also
1964 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 28 |
Followed by Problem 30 | |
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All AHSME Problems and Solutions |
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