Difference between revisions of "1958 AHSME Problems/Problem 14"
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At a dance party a group of boys and girls exchange dances as follows: one boy dances with <math> 5</math> girls, a second boy dances with <math> 6</math> girls, and so on, the last boy dancing with all the girls. If <math> b</math> represents the number of boys and <math> g</math> the number of girls, then: | At a dance party a group of boys and girls exchange dances as follows: one boy dances with <math> 5</math> girls, a second boy dances with <math> 6</math> girls, and so on, the last boy dancing with all the girls. If <math> b</math> represents the number of boys and <math> g</math> the number of girls, then: | ||
− | <math> \textbf{(A)}\ b | + | <math> \textbf{(A)}\ b = g\qquad |
− | \textbf{(B)}\ b | + | \textbf{(B)}\ b = \frac{g}{5}\qquad |
− | \textbf{(C)}\ b | + | \textbf{(C)}\ b = g - 4\qquad |
− | \textbf{(D)}\ b | + | \textbf{(D)}\ b = g - 5\qquad \\ |
− | \textbf{(E)}\ \text{It is impossible to determine a relation between }{b}\text{ and }{g}\text{ without knowing }{b | + | \textbf{(E)}\ \text{It is impossible to determine a relation between }{b}\text{ and }{g}\text{ without knowing }{b + g.}</math> |
Revision as of 23:18, 13 March 2015
Problem
At a dance party a group of boys and girls exchange dances as follows: one boy dances with girls, a second boy dances with
girls, and so on, the last boy dancing with all the girls. If
represents the number of boys and
the number of girls, then:
Solution
See Also
1958 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 13 |
Followed by Problem 15 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 • 31 • 32 • 33 • 34 • 35 • 36 • 37 • 38 • 39 • 40 • 41 • 42 • 43 • 44 • 45 • 46 • 47 • 48 • 49 • 50 | ||
All AHSME Problems and Solutions |
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