Difference between revisions of "1958 AHSME Problems/Problem 14"
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== Solution == | == Solution == | ||
− | <math>\fbox{}</math> | + | After inspection, we notice a general pattern: the <math>n^th</math> boy dances with <math>n + 4</math> girls. |
+ | Since the last boy dances with all the girls, there must be four more girls than guys. | ||
+ | |||
+ | Therefore, the equation that relates them is <math>\fbox{(C) b = g - 4}</math> | ||
== See Also == | == See Also == |
Revision as of 01:49, 22 December 2015
Problem
At a dance party a group of boys and girls exchange dances as follows: one boy dances with girls, a second boy dances with
girls, and so on, the last boy dancing with all the girls. If
represents the number of boys and
the number of girls, then:
Solution
After inspection, we notice a general pattern: the boy dances with
girls.
Since the last boy dances with all the girls, there must be four more girls than guys.
Therefore, the equation that relates them is
See Also
1958 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 13 |
Followed by Problem 15 | |
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All AHSME Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.