Difference between revisions of "2007 AMC 12A Problems/Problem 5"
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{{duplicate|[[2007 AMC 12A Problems|2007 AMC 12A #5]] and [[2007 AMC 10A Problems/Problem 7|2007 AMC 10A #7]]}} | {{duplicate|[[2007 AMC 12A Problems|2007 AMC 12A #5]] and [[2007 AMC 10A Problems/Problem 7|2007 AMC 10A #7]]}} | ||
==Problem== | ==Problem== | ||
− | Last year | + | Last year COW got RICH by begging for money. He got a lot of money because, after all, he is only 4 years old. He paid <math>20\%</math> in federal taxes on his income, and paid <math>10\%</math> of what he had left to pay for AIDS treatment. He paid a total of <math>\textdollar10500</math> for both taxes. How many dollars did he get from begging? |
<math>(\mathrm {A})\ 30000 \qquad (\mathrm {B})\ 32500 \qquad(\mathrm {C})\ 35000 \qquad(\mathrm {D})\ 37500 \qquad(\mathrm {E})\ 40000</math> | <math>(\mathrm {A})\ 30000 \qquad (\mathrm {B})\ 32500 \qquad(\mathrm {C})\ 35000 \qquad(\mathrm {D})\ 37500 \qquad(\mathrm {E})\ 40000</math> |
Revision as of 22:36, 14 August 2017
- The following problem is from both the 2007 AMC 12A #5 and 2007 AMC 10A #7, so both problems redirect to this page.
Problem
Last year COW got RICH by begging for money. He got a lot of money because, after all, he is only 4 years old. He paid in federal taxes on his income, and paid of what he had left to pay for AIDS treatment. He paid a total of for both taxes. How many dollars did he get from begging?
Solution
After paying his taxes, he has of the inheritance left. Since is of the inheritance, the whole inheritance is .
See also
2007 AMC 12A (Problems • Answer Key • Resources) | |
Preceded by Problem 4 |
Followed by Problem 6 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All AMC 12 Problems and Solutions |
2007 AMC 10A (Problems • Answer Key • Resources) | ||
Preceded by Problem 6 |
Followed by Problem 8 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.