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Difference between revisions of "1983 AHSME Problems/Problem 5"

(→‎Solution)
(→‎Solution)
Line 8: Line 8:
 
B=(2,0);
 
B=(2,0);
 
C=(0,0);
 
C=(0,0);
−
pair A,B,C;
+
pair (A,B,C);
−
draw (A--B--C--A);
+
draw (A - - B - - C - - A);
 
</asy>
 
</asy>
  

Revision as of 06:27, 18 May 2016

Problem 5

Triangle $ABC$ has a right angle at $C$. If $\sin A = \frac{2}{3}$, then $\tan B$ is

$\textbf{(A)}\ \frac{3}{5}\qquad \textbf{(B)}\ \frac{\sqrt 5}{3}\qquad \textbf{(C)}\ \frac{2}{\sqrt 5}\qquad \text{(D)}\ \sqrt{3}\qquad \text{(E)}\ 2$

Solution

A=(0,1.7);
B=(2,0);
C=(0,0);
pair (A,B,C);
draw (A - - B - - C - - A);
 (Error making remote request. Unknown error_msg)

See Also

1983 AHSME (Problems • Answer Key • Resources)
Preceded by
Problem 4 		Followed by
Problem 6
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30
All AHSME Problems and Solutions


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