Difference between revisions of "1952 AHSME Problems/Problem 34"

(Solution)
(Solution)
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== Solution ==
 
== Solution ==
<math>\fbox{10000/10000-</math>p^2<math> (choice E)}</math>
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<math>\fbox{\frac{10000}{10000} (choice E)}</math>
  
 
== See also ==
 
== See also ==

Revision as of 12:25, 16 December 2017

Problem

The price of an article was increased $p\%$. Later the new price was decreased $p\%$. If the last price was one dollar, the original price was:

$\textbf{(A)}\ \frac{1-p^2}{200}\qquad \textbf{(B)}\ \frac{\sqrt{1-p^2}}{100}\qquad \textbf{(C)}\ \text{one dollar}\qquad\\ \textbf{(D)}\ 1-\frac{p^2}{10000-p^2}\qquad \textbf{(E)}\ \frac{10000}{10000-p^2}$

Solution

$\fbox{\frac{10000}{10000} (choice E)}$ (Error compiling LaTeX. Unknown error_msg)

See also

1952 AHSC (ProblemsAnswer KeyResources)
Preceded by
Problem 33
Followed by
Problem 35
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All AHSME Problems and Solutions

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