Difference between revisions of "2020 AIME I Problems/Problem 8"
(→Solution) |
(→Solution 1 (Coordinates)) |
||
| Line 20: | Line 20: | ||
<math>\frac{315}{64} \cdot \frac{64}{63} = 5</math>, <math>\frac{105\sqrt{3}}{64} \cdot \frac{64}{63} = \frac{5\sqrt{3}}{3}</math>. | <math>\frac{315}{64} \cdot \frac{64}{63} = 5</math>, <math>\frac{105\sqrt{3}}{64} \cdot \frac{64}{63} = \frac{5\sqrt{3}}{3}</math>. | ||
Therefore, the coordinates of point <math>P</math> are <math>(5,\frac{5\sqrt{3}}{3})</math>, so using the Pythagorean Theorem, <math>OP^2 = \frac{100}{3}</math>, for an answer of <math>\boxed{103}</math>. | Therefore, the coordinates of point <math>P</math> are <math>(5,\frac{5\sqrt{3}}{3})</math>, so using the Pythagorean Theorem, <math>OP^2 = \frac{100}{3}</math>, for an answer of <math>\boxed{103}</math>. | ||
| + | |||
| + | -molocyxu | ||
==See Also== | ==See Also== | ||
Revision as of 16:18, 12 March 2020
Note: Please do not post problems here until after the AIME.
Problem
Solution 1 (Coordinates)
We plot this on the coordinate grid with point 
as the origin. We will keep a tally of the x-coordinate and y-coordinate separately.
First move: The ant moves right 
.
Second move: We use properties of a 
triangle to get 
right, 
up.
Third move: 
left, 
up.
Fourth move: left.
Fifth move: 
left, 
down.
Sixth move: 
right, 
down.
Total of x-coordinate: 
.
Total of y-coordinate: 
.
After this cycle of six moves, all moves repeat with a factor of 
. Using the formula for a geometric series, multiplying each sequence by 
will give us the point 
.
, 
.
Therefore, the coordinates of point are 
, so using the Pythagorean Theorem, 
, for an answer of 
.
-molocyxu
See Also
| 2020 AIME I (Problems • Answer Key • Resources) | ||
| Preceded by Problem 7 |
Followed by Problem 9 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 | ||
| All AIME Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
