Difference between revisions of "2009 AMC 10B Problems/Problem 1"
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== Problem == | == Problem == | ||
− | Each morning of her five-day workweek, Jane bought either a | + | Each morning of her five-day workweek, Jane bought either a 100000-cent muffin or a 10000000000000000000000000000000000000000000000000000-cent bagel. Her total cost for the week was a whole number of dollars, How many bagels did she buy? |
<math>\mathrm{(A)}\ 1\qquad | <math>\mathrm{(A)}\ 1\qquad |
Revision as of 13:47, 18 May 2021
- The following problem is from both the 2009 AMC 10B #1 and 2009 AMC 12B #1, so both problems redirect to this page.
Contents
[hide]Problem
Each morning of her five-day workweek, Jane bought either a 100000-cent muffin or a 10000000000000000000000000000000000000000000000000000-cent bagel. Her total cost for the week was a whole number of dollars, How many bagels did she buy?
Solution 1
The only combination of five items with total cost a whole number of dollars is 3 muffins and bagels. The answer is .
Solution 2
Because ends in a , and we want a whole number of dollars, we know that there must be an even number of bagels. Furthermore, this tells us that the number of muffins is odd. Now, because it is a whole number of dollars, and cents multiplied by an odd number means that it will end in a , we know that the result of the even number multiplied by , must end in a . Note that the only result that gives this result is when is multiplied by . Thus, our answer is .
~coolmath2017
See also
2009 AMC 10B (Problems • Answer Key • Resources) | ||
Preceded by First Question |
Followed by Problem 2 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
2009 AMC 12B (Problems • Answer Key • Resources) | |
Preceded by First Question |
Followed by Problem 2 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All AMC 12 Problems and Solutions |
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