Difference between revisions of "2021 Fall AMC 12B Problems/Problem 3"
(→Solution 1) |
(→Solution 1) |
||
Line 15: | Line 15: | ||
<math>(M-5)+2=(L+3)</math> | <math>(M-5)+2=(L+3)</math> | ||
− | Plug in <math>M=L+N</math> to solve the two equations respectively to get <math>N=10</math> or <math>N=6</math>. Hence the answer is <math>60 \ | + | Plug in <math>M=L+N</math> to solve the two equations respectively to get <math>N=10</math> or <math>N=6</math>. Hence the answer is <math>60 \Rightarrow \boxed{(\textbf{C}) }.</math> |
~Wilhelm Z | ~Wilhelm Z |
Revision as of 02:53, 24 November 2021
Problem
At noon on a certain day, Minneapolis is degrees warmer than St. Louis. At
the temperature in Minneapolis has fallen by
degrees while the temperature in St. Louis has risen by
degrees, at which time the temperatures in the two cities differ by
degrees. What is the product of all possible values of
Solution 1
Let the temperature of Minneapolis be , and that of St. Louis be
. We have
.
At , either
or
Plug in to solve the two equations respectively to get
or
. Hence the answer is
~Wilhelm Z
2021 Fall AMC 12B (Problems • Answer Key • Resources) | |
Preceded by Problem 2 |
Followed by Problem 4 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All AMC 12 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.