Difference between revisions of "2021 Fall AMC 12B Problems/Problem 2"
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− | <math>Area=3*2=\boxed{(\textbf{B})\ 6}</math>. | + | <math>Area=2*Triangle=2*(\frac{1}{2}*3*2)=\boxed{(\textbf{B})\ 6}</math>. |
~Wilhelm Z | ~Wilhelm Z |
Revision as of 20:50, 24 November 2021
Problem
What is the area of the shaded figure shown below?
Solution 1
By inspection
.
~Wilhelm Z
Discussion
To find the area of the figure, it can be divided along the line into two congruent triangles, or the area of the triangle with vertices
,
, and
can be subtracted from the area of the triangle with vertices
,
, and
. Alternatively, Pick's Theorem or the Shoelace Theorem can be used.
2021 Fall AMC 12B (Problems • Answer Key • Resources) | |
Preceded by Problem 1 |
Followed by Problem 3 |
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All AMC 12 Problems and Solutions |
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