Difference between revisions of "2018 AIME II Problems/Problem 8"
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A diagram of the numbers: | A diagram of the numbers: | ||
− | + | <asy> | |
+ | import graph; | ||
+ | add(shift(0,0)*grid(4,4)); | ||
+ | label((0,0), "1", SW); | ||
+ | label((1,0), "1", SW); | ||
+ | label((2,0), "2", SW); | ||
+ | label((3,0), "3", SW); | ||
+ | label((4,0), "5", SW); | ||
− | 3 | + | label((0,1), "1", SW); |
+ | label((1,1), "2", SW); | ||
+ | label((2,1), "5", SW); | ||
+ | label((3,1), "10", SW); | ||
+ | label((4,1), "20", SW); | ||
− | 2 | + | label((0,2), "2", SW); |
+ | label((1,2), "5", SW); | ||
+ | label((2,2), "14", SW); | ||
+ | label((3,2), "32", SW); | ||
+ | label((4,2), "71", SW); | ||
− | 1 | + | label((0,3), "3", SW); |
+ | label((1,3), "10", SW); | ||
+ | label((2,3), "32", SW); | ||
+ | label((3,3), "84", SW); | ||
+ | label((4,3), "207", SW); | ||
− | 1 | + | label((0,4), "5", SW); |
+ | label((1,4), "20", SW); | ||
+ | label((2,4), "71", SW); | ||
+ | label((3,4), "207", SW); | ||
+ | label((4,4), "556", SW); | ||
+ | </asy> | ||
==Solution 2== | ==Solution 2== |
Revision as of 20:26, 12 January 2022
Contents
[hide]Problem
A frog is positioned at the origin of the coordinate plane. From the point , the frog can jump to any of the points , , , or . Find the number of distinct sequences of jumps in which the frog begins at and ends at .
Solution 1
We solve this problem by working backwards. Notice, the only points the frog can be on to jump to in one move are and . This applies to any other point, thus we can work our way from to , recording down the number of ways to get to each point recursively.
, , ,
A diagram of the numbers:
Solution 2
We'll refer to the moves , , , and as , , , and , respectively. Then the possible sequences of moves that will take the frog from to are all the permutations of , , , , , , , , and . We can reduce the number of cases using symmetry.
Case 1:
There are possibilities for this case.
Case 2: or
There are possibilities for this case.
Case 3:
There are possibilities for this case.
Case 4: or
There are possibilities for this case.
Case 5: or
There are possibilities for this case.
Case 6:
There are possibilities for this case.
Adding up all these cases gives us ways.
Solution 3 (General Case)
Mark the total number of distinct sequences of jumps for the frog to reach the point as . Consider for each point in the first quadrant, there are only possible points in the first quadrant for frog to reach point , and these points are . As a result, the way to count is
Also, for special cases,
Start with , use this method and draw the figure below, we can finally get (In order to make the LaTeX thing more beautiful to look at, I put to make every number digits)
So the total number of distinct sequences of jumps for the frog to reach is .
~Solution by (Frank FYC)
Solution 4 (Casework)
Casework Solution: x-distribution: 1-1-1-1 (1 way to order) y-distribution: 1-1-1-1 (1 way to order) ways total
x-distribution: 1-1-1-1 (1 way to order) y-distribution: 1-1-2 (3 ways to order) ways total
x-distribution: 1-1-1-1 (1 way to order) y-distribution: 2-2 (1 way to order) ways total
x-distribution: 1-1-2 (3 ways to order) y-distribution: 1-1-1-1 (1 way to order) ways total
x-distribution: 1-1-2 (3 ways to order) y-distribution: 1-1-2 (3 ways to order) ways total
x-distribution: 1-1-2 (3 ways to order) y-distribution: 2-2 (1 way to order) ways total
x-distribution: 2-2 (1 way to order) y-distribution: 1-1-1-1 (1 way to order) ways total
x-distribution: 2-2 (1 way to order) y-distribution: 1-1-2 (3 ways to order) ways total
x-distribution: 2-2 (1 way to order) y-distribution: 2-2 (1 way to order) ways total
-fidgetboss_4000
Video Solution
On The Spot STEM : https://www.youtube.com/watch?v=v2fo3CaAhmM
See Also
2018 AIME II (Problems • Answer Key • Resources) | ||
Preceded by Problem 7 |
Followed by Problem 9 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 | ||
All AIME Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.