Difference between revisions of "2023 AMC 12A Problems/Problem 2"
(→Solution 2) |
|||
Line 15: | Line 15: | ||
==Solution 2== | ==Solution 2== | ||
− | Let <math>p | + | Let <math>p</math> be the weight of a pizza. |
− | <math>o | + | <math>o</math> be the weight of a cup of orange. |
From the problem, we know that <math>o = \frac{1}{4}</math>. | From the problem, we know that <math>o = \frac{1}{4}</math>. |
Revision as of 19:50, 9 November 2023
Contents
Problem
The weight of of a large pizza together with cups of orange slices is the same as the weight of of a large pizza together with cup of orange slices. A cup of orange slices weighs of a pound. What is the weight, in pounds, of a large pizza?
Solution 1
Use a system of equations. Let be the weight of a pizza and be the weight of a cup of orange slices. We have Rearranging, we get Plugging in pounds for gives
~ItsMeNoobieboy
Solution 2
Let be the weight of a pizza.
be the weight of a cup of orange.
From the problem, we know that .
Write the equation below:
Solving for :
~d_code
See Also
2023 AMC 10A (Problems • Answer Key • Resources) | ||
Preceded by Problem 1 |
Followed by Problem 3 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
2023 AMC 12A (Problems • Answer Key • Resources) | |
Preceded by Problem 1 |
Followed by Problem 3 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All AMC 12 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.