Difference between revisions of "1958 AHSME Problems/Problem 20"

m (Problem)
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== Solution ==
 
== Solution ==
<math>\fbox{}</math>
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We could rewrite <math>4ˆx - 4ˆ(x-1) = 24</math> as <math>
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</math>\fbox{}$
  
 
== See Also ==
 
== See Also ==

Latest revision as of 15:12, 6 August 2024

Problem

If $4^x - 4^{x - 1} = 24$, then $(2x)^x$ equals:

$\textbf{(A)}\ 5\sqrt{5}\qquad  \textbf{(B)}\ \sqrt{5}\qquad  \textbf{(C)}\ 25\sqrt{5}\qquad  \textbf{(D)}\ 125\qquad  \textbf{(E)}\ 25$

Solution

We could rewrite $4ˆx - 4ˆ(x-1) = 24$ (Error compiling LaTeX. Unknown error_msg) as $$ (Error compiling LaTeX. Unknown error_msg)\fbox{}$

See Also

1958 AHSC (ProblemsAnswer KeyResources)
Preceded by
Problem 19
Followed by
Problem 21
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50
All AHSME Problems and Solutions

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