Difference between revisions of "2012 AMC 12B Problems/Problem 2"

(See Also)
Line 11: Line 11:
 
== See Also ==
 
== See Also ==
  
{{AMC12 box|year=2012|ab=B|num-b=2|num-a=2}}
+
{{AMC12 box|year=2012|ab=B|num-b=1|num-a=3}}

Revision as of 21:48, 12 January 2013

Problem

A circle of radius 5 is inscribed in a rectangle as shown. The ratio of the length of the rectangle to its width is 2:1. What is the area of the rectangle?

$\textbf{(A)}\ 50\qquad\textbf{(B)}\ 100\qquad\textbf{(C)}\ 125\qquad\textbf{(D)}\ 150\qquad\textbf{(E)}\ 200$


Solution

If the radius is $5$, then the width is $10$, hence the length is $20$. $10\times20=200$, $\boxed{\text{E}}$

See Also

2012 AMC 12B (ProblemsAnswer KeyResources)
Preceded by
Problem 1
Followed by
Problem 3
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 12 Problems and Solutions