Difference between revisions of "2012 AMC 12B Problems/Problem 4"
Username222 (talk | contribs) (→Problem) |
Username222 (talk | contribs) (Rewrote solution.) |
||
| Line 7: | Line 7: | ||
==Solution== | ==Solution== | ||
| − | + | The ratio <math>\frac{400 \text{ euros}}{500 \text{ dollars}}</math> can be simplified using simple dimensional analysis: | |
| + | |||
| + | <math>\frac{400 \text{ euros}}{500 \text{ dollars}} \cdot \frac{1.3 \text{ dollars}}{1 \text{ euro}} = \frac{520}{500} = 1.04</math>, which means a value that is greater by <math>\boxed{ \textbf{(B)} \ 4 }</math> percent. | ||
| + | |||
| + | |||
== See Also == | == See Also == | ||
{{AMC12 box|year=2012|ab=B|num-b=3|num-a=5}} | {{AMC12 box|year=2012|ab=B|num-b=3|num-a=5}} | ||
Revision as of 22:41, 12 January 2013
Problem
Suppose that the euro is worth 1.3 dollars. If Diana has 500 dollars and Etienne has 400 euros, by what percent is the value of Etienne's money greater that the value of Diana's money?
Solution
The ratio 
can be simplified using simple dimensional analysis:
, which means a value that is greater by 
percent.
See Also
| 2012 AMC 12B (Problems • Answer Key • Resources) | |
| Preceded by Problem 3 |
Followed by Problem 5 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
