Difference between revisions of "2013 AIME II Problems/Problem 1"
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==Solution== | ==Solution== | ||
− | There are <math>24*60=1440</math> normal minutes in a day , and <math>10*100=1000</math> metric minutes in a day. The ratio of normal to metric minutes in a day is <math>\frac{1440}{1000}</math>, which simplifies to <math>\frac{36}{25}</math>. This means that every time 36 normal minutes pass, 25 metric minutes pass. From midnight to <math>\text{6:36}</math> AM, <math>6*60+36=396</math> normal minutes pass. This can be viewed as <math>\frac{396}{36}=11</math> cycles of 36 normal minutes, so 11 cycles of 25 metric minutes pass. Adding <math>25*11=275</math> to <math>\text{0:00}</math> gives <math>\text{2:75}</math>, so the answer is <math>\boxed{275}</math> | + | There are <math>24*60=1440</math> normal minutes in a day , and <math>10*100=1000</math> metric minutes in a day. The ratio of normal to metric minutes in a day is <math>\frac{1440}{1000}</math>, which simplifies to <math>\frac{36}{25}</math>. This means that every time 36 normal minutes pass, 25 metric minutes pass. From midnight to <math>\text{6:36}</math> AM, <math>6*60+36=396</math> normal minutes pass. This can be viewed as <math>\frac{396}{36}=11</math> cycles of 36 normal minutes, so 11 cycles of 25 metric minutes pass. Adding <math>25*11=275</math> to <math>\text{0:00}</math> gives <math>\text{2:75}</math>, so the answer is <math>\boxed{275}</math>. |
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+ | == See also == | ||
+ | {{AIME box|year=2013|n=II|before=First Problem|num-a=2}} |
Revision as of 15:34, 6 April 2013
Suppose that the measurement of time during the day is converted to the metric system so that each day has metric hours, and each metric hour has metric minutes. Digital clocks would then be produced that would read just before midnight, at midnight, at the former AM, and at the former PM. After the conversion, a person who wanted to wake up at the equivalent of the former AM would set his new digital alarm clock for , where , , and are digits. Find .
Solution
There are normal minutes in a day , and metric minutes in a day. The ratio of normal to metric minutes in a day is , which simplifies to . This means that every time 36 normal minutes pass, 25 metric minutes pass. From midnight to AM, normal minutes pass. This can be viewed as cycles of 36 normal minutes, so 11 cycles of 25 metric minutes pass. Adding to gives , so the answer is .
See also
2013 AIME II (Problems • Answer Key • Resources) | ||
Preceded by First Problem |
Followed by Problem 2 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 | ||
All AIME Problems and Solutions |