Difference between revisions of "2012 AMC 8 Problems/Problem 16"
m |
|||
| Line 15: | Line 15: | ||
==See Also== | ==See Also== | ||
{{AMC8 box|year=2012|num-b=15|num-a=17}} | {{AMC8 box|year=2012|num-b=15|num-a=17}} | ||
| + | {{MAA Notice}} | ||
Revision as of 15:37, 3 July 2013
Problem
Each of the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, and 9 is used only once to make two five-digit numbers so that they have the largest possible sum. Which of the following could be one of the numbers?
Solution
In order to maximize the sum of the numbers, the numbers must have their digits ordered in decreasing value. There are only two numbers from the answer choices with this property: 
and 
. To determine the answer we will have to use estimation and the first two digits of the numbers.
For the number that would maximize the sum would start with 
. The first two digits of (when rounded) are 
. Adding and , we find that the first three digits of the sum of the two numbers would be 
.
For the number that would maximize the sum would start with 
. The first two digits of (when rounded) are 
. Adding and , we find that the first three digits of the sum of the two numbers would be 
.
From the estimations, we can say that the answer to this problem is 
.
See Also
| 2012 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 15 |
Followed by Problem 17 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
