Difference between revisions of "2012 AMC 12B Problems/Problem 1"
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== Problem == | == Problem == | ||
− | Each third-grade classroom at Downtown Detroit Elementary has 18 students and 2 pet | + | Each third-grade classroom at Downtown Detroit Elementary has 18 students and 2 pet rabbits. How many more students than rabbits are there in all 4 of the third-grade classrooms? |
<math> \textbf{(A)}\ 48\qquad\textbf{(B)}\ 56\qquad\textbf{(C)}\ 64\qquad\textbf{(D)}\ 72\qquad\textbf{(E)}\ 80 </math> | <math> \textbf{(A)}\ 48\qquad\textbf{(B)}\ 56\qquad\textbf{(C)}\ 64\qquad\textbf{(D)}\ 72\qquad\textbf{(E)}\ 80 </math> |
Revision as of 22:52, 28 January 2014
- The following problem is from both the 2012 AMC 12B #1 and 2012 AMC 10B #1, so both problems redirect to this page.
Contents
[hide]Problem
Each third-grade classroom at Downtown Detroit Elementary has 18 students and 2 pet rabbits. How many more students than rabbits are there in all 4 of the third-grade classrooms?
Solution
Solution 1
Multiplying and by we get students and rabbits. We then subtract:
Solution 2
In each class, there are more students than rabbits. So for all classrooms, the difference between students and rabbits is
See Also
2012 AMC 12B (Problems • Answer Key • Resources) | |
Preceded by ' |
Followed by Problem 2 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All AMC 12 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.