Difference between revisions of "1958 AHSME Problems/Problem 20"
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== Problem == | == Problem == | ||
| − | If <math> 4^x | + | If <math> 4^x - 4^{x - 1} = 24</math>, then <math> (2x)^x</math> equals: |
<math> \textbf{(A)}\ 5\sqrt{5}\qquad | <math> \textbf{(A)}\ 5\sqrt{5}\qquad | ||
Revision as of 22:19, 13 March 2015
Problem
If 
, then 
equals:
Solution
See Also
| 1958 AHSC (Problems • Answer Key • Resources) | ||
| Preceded by Problem 19 |
Followed by Problem 21 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 • 31 • 32 • 33 • 34 • 35 • 36 • 37 • 38 • 39 • 40 • 41 • 42 • 43 • 44 • 45 • 46 • 47 • 48 • 49 • 50 | ||
| All AHSME Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
