Difference between revisions of "1983 AHSME Problems/Problem 25"
Quantummech (talk | contribs) (→Solution) |
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<cmath>4=\frac{60}{60^a 60^b}=60^(1-a-b).</cmath> | <cmath>4=\frac{60}{60^a 60^b}=60^(1-a-b).</cmath> | ||
Therefore, we have: | Therefore, we have: | ||
− | <cmath>60^{(1-a-b)/2}=4^{1/2}=\fbox{\textbf{(B) 2 | + | <cmath>60^{(1-a-b)/2}=4^{1/2}=\fbox{\textbf{(B)} 2}</cmath> |
==See Also== | ==See Also== |
Revision as of 06:49, 18 May 2016
Problem 25
If and
, then
is
Solution
We have that . We can substitute our value for 5, to get:
Therefore we have:
Since
, we have:
Therefore, we have:
See Also
1983 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 24 |
Followed by Problem 26 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
All AHSME Problems and Solutions |
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