Difference between revisions of "2017 AMC 8 Problems/Problem 7"
(→Solution 1) |
(→Solution 2) |
||
Line 11: | Line 11: | ||
==Solution 2== | ==Solution 2== | ||
− | Let | + | Let |
==See Also== | ==See Also== |
Revision as of 11:58, 11 January 2018
Contents
Problem 7
Let be a 6-digit positive integer, such as 247247, whose first three digits are the same as its last three digits taken in the same order. Which of the following numbers must also be a factor of
?
Solution 1
Let Clearly,
is divisible by
.
Solution 2
Let
See Also
2017 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 6 |
Followed by Problem 8 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.