Difference between revisions of "2017 AMC 8 Problems/Problem 1"

Revision as of 02:41, 10 August 2018

Problem 1

Which of the following values is largest?

$\textbf{(A) }2+0+1+7\qquad\textbf{(B) }2 \times 0 +1+7\qquad\textbf{(C) }2+0 \times 1 + 7\qquad\textbf{(D) }2+0+1 \times 7\qquad\textbf{(E) }2 \times 0 \times 1 \times 7$

Solution 1

We compute each expression individually according to the order of operations. We get $2 + 0 + 1 + 7 = 10$ , $2 \times 0 + 1 + 7 = 8$ , $2 + 0 \times 1 + 7 = 9$ , $2 + 0 + 1 \times 7 = 9$ , and $2 \times 0 \times 1 \times 7 = 0$ . Since $10$ is the greatest out of these numbers, $\boxed{\textbf{(A) }2+0+1+7}$ is the answer.

Solution 1

We immediately see that every one of the choices, except for A, has a number multiplied by $0$ . This will only make the expression's value smaller. Therefore, $\boxed{\textbf{(A) }2+0+1+7}$ is your answer

2017 AMC 8 (Problems • Answer Key • Resources)
Preceded by First Problem	Followed by Problem 2
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AJHSME/AMC 8 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.

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 ==Solution 1==
-We immediately see that each of the other choices, except for A, has a number multiplied by <math>0</math>. This will only make the expression's value smaller, obviously. Therefore <math>\boxed{\textbf{(A) }2+0+1+7}</math> is your answer
+We immediately see that every one of the choices, except for A, has a number multiplied by <math>0</math>. This will only make the expression's value smaller. Therefore, <math>\boxed{\textbf{(A) }2+0+1+7}</math> is your answer
 ==See Also==

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Difference between revisions of "2017 AMC 8 Problems/Problem 1"

Revision as of 02:41, 10 August 2018

Contents

Problem 1

Solution 1

Solution 1

See Also