2005 AMC 10A Problems/Problem 4
Contents
Problem
A rectangle with a diagonal of length and the length is twice as long as the width. What is the area of the rectangle?
Video Solution
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Solution
Let's set our length to and our width to
.
We have our area as and our diagonal:
as
Now we can plug this value into the answer choices and test which one will give our desired area of .
- All of the answer choices have our
value squared, so keep in mind that
Through testing, we see that
So our correct answer choice is
-JinhoK
See also
2005 AMC 10A (Problems • Answer Key • Resources) | ||
Preceded by Problem 3 |
Followed by Problem 5 | |
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All AMC 10 Problems and Solutions |
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