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2006 Cyprus MO/Lyceum/Problems

Revision as of 11:42, 24 October 2007 by Inscrutableroot (talk | contribs) (→‎Problem 19)

Problem 1

A diary industry, in a quantity of milk with $4\%$ fat adds a quantity of milk with $1\%$ fat and produces $1200$kg of milk with $2\%$ fat. The quantity of milk with $1\%$ fat, that was added is (in kg)

A. $1000$

B. $600$

C. $800$

D. $120$

E. $480$

Solution

Problem 2

The operation $\alpha * \beta$ is defined by $\alpha * \beta = \alpha^2 - \beta^2$ $\forall \alpha , \beta \in R$. The value of the expression $K = \left[\left(1+\sqrt{3}\right) * 2\right]*\sqrt{2}$ is

A. $3$

B. $0$

C. $\sqrt{3}$

D. $9$

E. $1$

Solution

Problem 3

The domain of the function $f(x)=\sqrt{4+2x}$ is

A. $(-2,+\infty)$

B. $[0,+\infty)$

C. $[-2,+\infty)$

D. $[-2,0]$

E. $R$

Solution

Problem 4

Given the function $f(x)=\alpha x^2 +9x+ \frac{81}{4\alpha}$ , $\alpha \neq 0$ Which of the following is correct, about the graph of $f$?

A. intersects x-axis

B. touches y-axis

C. touches x-axis

D. has minimum point

E. has maximum point

Solution

Problem 5

If both integers $\alpha,\beta$ are bigger than 1 and satisfy $a^7=b^8$, then the minimum value of $\alpha+\beta$ is

A. $384$

B. $2$

C. $15$

D. $56$

E. $512$

Solution

Problem 6

The value of the expression $K=\sqrt{19+8\sqrt{3}}-\sqrt{7+4\sqrt{3}}$ is

A. $4$

B. $4\sqrt{3}$

C. $12+4\sqrt{3}$

D. $-2$

E. $2$

Solution

Problem 7

2006 CyMO-7.PNG

In the figure, $AB\Gamma$ is an equilateral triangle and $A\Delta \perp B\Gamma$, $\Delta E\perp A\Gamma$, $EZ\perp B\Gamma$. If $EZ=\sqrt{3}$, then the length of the side of the triangle $AB\Gamma$ is

A. $\frac{3\sqrt{3}}{2}$

B. $8$

C. $4$

D. $3$

E. $9$


Solution

Problem 8

2006 CyMO-8.PNG

In the figure $AB\Gamma \Delta E$ is a regular 5-sided polygon and $Z$, $H$, $\Theta$, $I$, $K$ are the points of intersections of the extensions of the sides. If the area of the "star" $AHB\Theta \Gamma I\Delta KEZA$ is 1, then the area of the shaded quadrilateral $A\Gamma IZ$ is

A. $\frac{2}{3}$

B. $\frac{1}{2}$

C. $\frac{3}{7}$

D. $\frac{3}{10}$

E. None of these

Solution

Problem 9

If $x=\sqrt[3]{4}$ and $y=\sqrt[3]{6}-\sqrt[3]{3}$, then which of the following is correct?

A. $x=y$

B. $x<y$

C. $x=2y$

D. $x>2y$

E. None of these

Solution

Problem 10

If $2^x=15$ and $15^y=256$, then the product $xy$ equals

A. $7$

B. $3$

C. $1$

D. $8$

E. $6$

Solution

Problem 11

2006 CyMO-11.PNG

The lines $(\epsilon):x-2y=0$ and $(\delta):x+y=4$ intersect at the point $\Gamma$. If the line $(\delta)$ intersects the axes $Ox$ and $Oy$ to the points $A$ and $B$ respectively, then the ratio of the area of the triangle $OA\Gamma$ to the area of the triangle $OB\Gamma$ equals

A. $\frac{1}{3}$

B. $\frac{2}{3}$

C. $\frac{3}{5}$

D. $\frac{1}{2}$

E. $\frac{4}{9}$

Solution

Problem 12

If $f(\alpha,\beta)= \begin{cases} \displaystyle \alpha & \textrm {if} \qquad \alpha=\beta \\ f(\alpha-\beta,\beta) & \textrm {if} \qquad \alpha>\beta \\ f(\beta-\alpha,\alpha) & \textrm {if} \qquad \alpha<\beta \end{cases}$

then $f(28,17)$ equals

A. $8$

B. $0$

C. $11$

D. $5$

E. $1$

Solution

Problem 13

The sum of the digits of the number $10^{2006}-2006$ is

A. $18006$

B. $20060$

C. $2006$

D. $18047$

E. None of these

Solution

Problem 14

2006 CyMO-14.PNG

The rectangle $AB\Gamma \Delta$ is a small garden divided to the rectangle $AZE\Delta$ and to the square $ZB\Gamma E$, so that $AE=2\sqrt{5}m$ and the shaded area of the triangle $\Delta BE$ is $4m^2$. The area of the whole garden is

A. $24m^2$

B. $20m^2$

C. $16m^2$

D. $32m^2$

E. $10\sqrt5m^2$

Solution

Problem 15

The expression :$\frac{1}{2+\sqrt7} + \frac{1}{\sqrt7+\sqrt{10}}+ \frac{1}{\sqrt{10}+\sqrt{13}} + \frac{1}{\sqrt{13}+4}$ equals

A. $\frac{3}{4}$

B. $\frac{3}{2}$

C. $\frac{2}{5}$

D. $\frac{1}{2}$

E. $\frac{2}{3}$

Solution

Problem 16

If $x_1,x_2$ are the roots of the equation $x^2-2kx+2m=0$, then $\frac{1}{x_1},\frac{1}{x_2}$ are the roots of the equation

A. $x^2-2k^2x+2m^2=0$

B. $x^2-\frac{k}{m}x+\frac{1}{2m}=0$

C. $x^2-\frac{m}{k}x+\frac{1}{2m}=0$

D. $2mx^2-kx+1=0$

E. $2kx^2-2mx+1=0$

Solution

Problem 17

2006 CyMO-17.PNG

$AB\Gamma$ is equilateral triangle of side $\alpha$ and $A\Delta=BE=\frac{\alpha}{3}$. The measure of the angle $\ang \Gamma PE$ (Error compiling LaTeX. Unknown error_msg) is

A. $60^{\circ}$

B. $50^{\circ}$

C. $40^{\circ}$

D. $45^{\circ}$

E. $70^{\circ}$

Solution

Problem 18

2006 CyMO-18.PNG

$K(k,0)$ is the minimum point of the parabola and the parabola intersects the y-axis at the point $\Gamma (0,k)$. If the area if the rectangle $OAB\Gamma$ is $8$, then the equation of the parabola is

A. $y=\frac{1}{2}(x+2)^2$

B. $y=\frac{1}{2}(x-2)^2$

C. $y=x^2+2$

D. $y=x^2-2x+1$

E. $y=x^2-4x+4$

Solution

Problem 19

2006 CyMO-19.PNG

In the figure, $AB\Gamma$ is an isosceles triangle with$AB=A\Gamma=\sqrt2$ and $\ang A=45^\circ$ (Error compiling LaTeX. Unknown error_msg). If $B\Delta$ is altitude of the triangle and the sector $B\Lambda \Delta KB$ belongs to the circle $(B,B\Delta )$, the area of the shaded region is

A. $\frac{4\sqrt3-\pi}{6}$

B. $4\left(\sqrt2-\frac{\pi}{3}\right)$

C. $\frac{8\sqrt2-3\pi}{16}$

D. $\frac{\pi}{8}$

E. None of these

Solution

Problem 20

The sequence $f:N \to R$ satisfies $f(n)=f(n-1)-f(n-2),\forall n\geq 3$. Given that $f(1)=f(2)=1$, then $f(3n)$ equals

A. $3$

B. $-3$

C. $2$

D. $1$

E. $0$

Solution

Problem 21

A convex polygon has $n$ sides and $740$ diagonals. Then $n$ equals

A. $30$

B. $40$

C. $50$

D. $60$

E. None of these

Solution

Problem 22

2006 CyMO-22.PNG

$AB\Gamma \Delta$ is rectangular and the points $K,\Lambda ,M,N$ lie on the sides $AB, B\Gamma , \Gamma \Delta, \Delta A$ respectively so that $\frac{AK}{KB}=\frac{BL}{L\Gamma}=\frac{\Gamma M}{M\Delta}=\frac{\Delta N}{NA}=2$. If $E_1$ is the area of $K\Lambda MN$ and $E_2$ is the area of the rectangle $AB\Gamma \Delta$, the ratio $\frac{E_1}{E_2}$ equals

A. $\frac{5}{9}$

B. $\frac{1}{3}$

C. $\frac{9}{5}$

D. $\frac{3}{5}$

E. None of these

Solution

Problem 23

Of $21$ students taking Mathematics, Physics and Chemistry, no student takes one subject only. The number of students taking Mathematics and Chemistry only, equals to four times the number taking Mathematics and Physics only. If the number of students taking Physics and Chemistry only equals to three times the number of students taking all three subjects, then the number of students taking all three subjects is

A. $0$

B. $5$

C. $2$

D. $4$

E. $1$

Solution

Problem 24

The number of divisors of the number $2006$ is

A. $3$

B. $4$

C. $8$

D. $5$

E. $6$

Solution

Problem 25

Solution

Problem 26

Solution

Problem 27

Solution

Problem 28

Solution

Problem 29

Solution

Problem 30

Solution

See also

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