2012 AMC 10A Problems/Problem 3

The following problem is from both the 2012 AMC 12A #1 and 2012 AMC 10A #3, so both problems redirect to this page.

Problem

A bug crawls along a number line, starting at -2. It crawls to -6, then turns around and crawls to 5. How many units does the bug crawl altogether?

$\textbf{(A)}\ 9\qquad\textbf{(B)}\ 11\qquad\textbf{(C)}\ 13\qquad\textbf{(D)}\ 14\qquad\textbf{(E)}\ 15$

Solution

Crawling from -2 to -6 takes it a distance of 4 units. Crawling from -6 to 5 takes it a distance of 11 units. Add 4 and 11 to get $\boxed{\textbf{(E)}\ 15}$

2012 AMC 10A (Problems • Answer Key • Resources)
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All AMC 10 Problems and Solutions

2012 AMC 12A (Problems • Answer Key • Resources)
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All AMC 12 Problems and Solutions

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2012 AMC 10A Problems/Problem 3

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