2012 AIME I Problems/Problem 10
Problem 10
Let be the set of all perfect squares whose rightmost three digits in base
are
. Let
be the set of all numbers of the form
, where
is in
. In other words,
is the set of numbers that result when the last three digits of each number in
are truncated. Find the remainder when the tenth smallest element of
is divided by
.
Solution
See also
2012 AIME I (Problems • Answer Key • Resources) | ||
Preceded by Problem 9 |
Followed by Problem 11 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 | ||
All AIME Problems and Solutions |