2012 AIME I Problems/Problem 4
Problem 4
Butch and Sundance need to get out of Dodge. To travel as quickly as possible, each alternates walking and riding their only horse, Sparky, as follows. Butch begins by walking while Sundance rides. When Sundance reaches the first of the hitching posts that are conveniently located at one-mile intervals along their route, he ties Sparky to the post and begins walking. When Butch reaches Sparky, he rides until he passes Sundance, then leaves Sparky at the next hitching post and resumes walking, and they continue in this manner. Sparky, Butch, and Sundance walk at
and
miles per hour, respectively. The first time Butch and Sundance meet at a milepost, they are
miles from Dodge, and they have been traveling for
minutes. Find
.
Solution
When they meet at the milepost, Sparky has been ridden for miles total. Assume Butch rides Sparky for
miles, and Sundance rides for
miles. Thus, we can set up an equation, given that Sparky takes
hours per mile, Butch takes
hours per mile, and Sundance takes
hours per mile:
The smallest possible integral value of is
, so we plug in
and
and get
hours, or
minutes. So our answer is
See also
2012 AIME I (Problems • Answer Key • Resources) | ||
Preceded by Problem 3 |
Followed by Problem 5 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 | ||
All AIME Problems and Solutions |