2012 AMC 12B Problems/Problem 10
Problem
What is the area of the polygon whose vertices are the points of intersection of the curves 
and 
Solution
The first curve is a circle with radius 5 centered at the origin, and the second curve is an ellipse with center (4,0) and end points of (-5,0) and (13,0). Finding points of intersection, we get (-5,0) (4,3) and (4,-3), forming a triangle with height of 9 and base of 6. So 9x6x0.5 =27 ; B.
See Also
| 2012 AMC 12B (Problems • Answer Key • Resources) | |
| Preceded by Problem 9 |
Followed by Problem 11 |
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| All AMC 12 Problems and Solutions | |
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