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  • ...imeter]] of <math> ABCD </math> is <math> 640 </math>. Find <math> \lfloor 1000 \cos A \rfloor. </math> (The notation <math> \lfloor x \rfloor </math> mean <math>\lfloor 1000 \cos A \rfloor = \boxed{777}</math>.
    3 KB (487 words) - 22:14, 24 November 2019
  • ...</math> and <math> n </math> are [[positive integer]]s with <math> m + n < 1000, </math> find <math> m + n. </math>
    2 KB (284 words) - 13:42, 10 October 2020
  • An [[integer]] between <math>1000</math> and <math>9999</math>, inclusive, is called ''balanced'' if the sum
    4 KB (696 words) - 11:55, 10 September 2023
  • ...be reduced any further and because the only answers on the AIME are below 1000, this cannot be the right answer. However, if we round up, <math>342/1024</
    15 KB (2,406 words) - 23:56, 23 November 2023
  • ...gits are the same. What is the remainder when <math>N</math> is divided by 1000? Therefore, the remainder when the number is divided by <math>1000</math> is <math>\boxed{120}</math>.
    1,013 bytes (162 words) - 09:00, 11 July 2023
  • ...ents.) Find the remainder obtained when <math>n</math> is divided by <math>1000</math>. ...th>n = \frac{1}{2}(3^{10}-2\cdot2^{10}+1) = 28501 \equiv \boxed{501} \pmod{1000}</math>.
    3 KB (404 words) - 23:07, 4 May 2024
  • Find the integer that is closest to <math>1000\sum_{n=3}^{10000}\frac1{n^2-4}</math>. And so, <math>1000\sum_{n=3}^{10,000} \frac{1}{n^2-4} = 1000\sum_{n=3}^{10,000} \frac{1}{4} \left( \frac{1}{n-2} - \frac{1}{n+2} \right)
    2 KB (330 words) - 05:56, 23 August 2022
  • ...sitive integer. Find the remainder when <math>m</math> is divided by <math>1000</math>. <math>m=361803</math>, <math>\dfrac{m}{1000}=361</math> Remainder <math>\boxed{803}</math>.
    2 KB (268 words) - 07:28, 13 September 2020
  • A scout troop buys <math>1000</math> candy bars at a price of five for &#36;<math>2</math>. They sell all
    12 KB (1,874 words) - 21:20, 23 December 2020
  • ...of numbers divisible by their LCM which is 36 which is <math> \left[\frac{1000}{36}\right]=27. </math> The answer is 138-27=111.
    9 KB (1,364 words) - 15:59, 21 July 2006
  • ...integer, find the remainder when <math>n^{2007}</math> is divided by <math>1000</math>. ...1000}</math> and so <math>3^{2007} \equiv 3^7 \equiv 2187 \equiv 187 \pmod{1000}</math>
    963 bytes (135 words) - 15:53, 3 April 2012
  • ...integer, find the remainder when <math>n^{2007}</math> is divided by <math>1000</math>.
    8 KB (1,355 words) - 14:54, 21 August 2020
  • ...t square]]. Find the [[remainder]] when <math>S</math> is divided by <math>1000.</math>
    1 KB (198 words) - 10:50, 4 April 2012
  • ...perfect square. Find the remainder when <math>S</math> is divided by <math>1000.</math>
    5 KB (848 words) - 23:49, 25 February 2017
  • Let's try converting 1000 base 10 into base 7. Basically, we are trying to find the solution to the <center><math> 1000 = a_0 + 7a_1 + 49a_2 + 343a_3+2401a_4+\cdots</math></center>
    7 KB (1,177 words) - 15:56, 18 April 2020
  • ...ech Math Meet]], with one of the students placing first and winning a &#36;1000 scholarship. The club had the 10th place winner at the UGA meet, and place
    4 KB (637 words) - 15:26, 25 September 2006
  • ...the remainder when <math>f(1)+f(2)+\cdots+f(99)</math> is divided by <math>1000</math>. ...if <math>k</math> has an even number of divisors. For how many <math>n \le 1000</math> does there exist an <math>A</math> such that <math>|A| = 620</math>
    8 KB (1,370 words) - 21:52, 27 February 2007
  • ...ts+2007</math>. Find the remainder when <math>S</math> is divided by <math>1000</math>.
    30 KB (4,794 words) - 23:00, 8 May 2024
  • 1000 - '''M''' ''(mille)''
    865 bytes (140 words) - 13:58, 24 March 2019
  • The full score is 1000, with each problem having equal weight in the score.
    2 KB (297 words) - 01:41, 21 January 2023

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