Create the page "Problem 6" on this wiki! See also the search results found.

Page title matches

• 2005 USAMO Problems/Problem 6
  == Problem ==
  4 KB (725 words) - 23:59, 29 March 2016
• 2009 AIME II Problems/Problem 6
  == Problem == problem is reduced to finding <math>B</math>.
  5 KB (921 words) - 00:15, 11 December 2022
• 2008 IMO Problems/Problem 6
  ==Problem== {{IMO box|year=2008|num-b=5|after=Last Problem}}
  1 KB (283 words) - 01:15, 19 November 2023
• 1988 AJHSME Problems/Problem 6
  ==Problem==
  936 bytes (108 words) - 12:04, 28 July 2020
• 1989 AJHSME Problems/Problem 6
  ==Problem== for(int a=0; a<6; ++a)
  995 bytes (157 words) - 17:07, 29 April 2021
• 1990 AJHSME Problems/Problem 6
  ==Problem==
  792 bytes (115 words) - 00:05, 5 July 2013
• 1964 IMO Problems/Problem 6
  == Problem ==
  4 KB (601 words) - 21:26, 21 November 2023
• 1965 IMO Problems/Problem 6
  == Problem == [https://i.imgur.com/hjGyVyg.png Image of problem Solution]. Credits to user '''awe-sum'''.
  545 bytes (96 words) - 12:52, 29 January 2021
• 2009 USAMO Problems/Problem 6
  == Problem == ...math>t_2</math> for sequence <math>t</math>. Then by the conditions of the problem, we have <math>(s_2 - s_1)(t_2 - t_1)</math> is an integer, or <math>(\frac
  2 KB (463 words) - 12:19, 21 August 2020
• 2009 IMO Problems/Problem 6
  == Problem == {{IMO box|year=2009|num-b=5|after=Last Problem}}
  5 KB (1,055 words) - 01:18, 19 November 2023
• 1991 AJHSME Problems/Problem 6
  ==Problem== 10 & 6 & 4 & 3 & 2 \\
  784 bytes (101 words) - 00:06, 5 July 2013
• 1961 AHSME Problems/Problem 6
  == Problem == <math>\textbf{(A)}\ 6\log{2} \qquad
  697 bytes (95 words) - 20:01, 17 May 2018
• 1989 IMO Problems/Problem 6
  ==Problem==
  11 KB (1,928 words) - 12:26, 26 July 2023
• 1999 AHSME Problems/Problem 6
  ==Problem==
  587 bytes (80 words) - 23:59, 16 March 2020
• 2010 AMC 12A Problems/Problem 6
  {{duplicate|[[2010 AMC 12A Problems|2010 AMC 12A #6]] and [[2010 AMC 10A Problems|2010 AMC 10A #9]]}} == Problem ==
  2 KB (320 words) - 04:51, 21 January 2023
• 2007 AMC 8 Problems/Problem 6
  == Problem ==
  764 bytes (115 words) - 12:22, 16 August 2021
• 2010 AIME I Problems/Problem 6
  == Problem == draw(graph(Q,min,max),linetype("6 2")+linewidth(0.7));
  6 KB (1,019 words) - 20:39, 20 November 2023
• 2010 AIME II Problems/Problem 6
  == Problem ==
  2 KB (426 words) - 17:47, 29 June 2022
• 2010 AMC 10B Problems/Problem 6
  ==Problem==
  2 KB (260 words) - 17:00, 1 August 2022
• 2010 USAJMO Problems/Problem 6
  #REDIRECT [[2010 USAMO Problems/Problem 4]]
  43 bytes (4 words) - 06:43, 3 June 2010

Page text matches

• 2006 AMC 12A Problems
  == Problem 1 == [[2006 AMC 12A Problems/Problem 1|Solution]]
  15 KB (2,223 words) - 13:43, 28 December 2020
• 2005 AMC 12A Problems
  == Problem 1 == [[2005 AMC 12A Problems/Problem 1|Solution]]
  13 KB (1,971 words) - 13:03, 19 February 2020
• 2004 AMC 12A Problems
  == Problem 1 == [[2004 AMC 12A Problems/Problem 1|Solution]]
  13 KB (1,953 words) - 00:31, 26 January 2023
• 2003 AMC 12A Problems
  == Problem 1 == [[2003 AMC 12A Problems/Problem 1|Solution]]
  13 KB (1,955 words) - 21:06, 19 August 2023
• 2002 AMC 12A Problems
  == Problem 1 == <math>(2x+3)(x-4)+(2x+3)(x-6)=0 </math>
  12 KB (1,792 words) - 13:06, 19 February 2020
• 2000 AMC 12 Problems
  == Problem 1 == [[2000 AMC 12 Problems/Problem 1|Solution]]
  13 KB (1,948 words) - 12:26, 1 April 2022
• 2001 AMC 12 Problems
  == Problem 1 == ...3\qquad \text{(B)}\ 3S + 2\qquad \text{(C)}\ 3S + 6 \qquad\text{(D)} 2S + 6 \qquad \text{(E)}\ 2S + 12</math>
  13 KB (1,957 words) - 12:53, 24 January 2024
• 2002 AMC 12B Problems
  == Problem 1 == \qquad\mathrm{(D)}\ 6
  10 KB (1,547 words) - 04:20, 9 October 2022
• 2003 AMC 12B Problems
  == Problem 1 == <cmath>\frac{2-4+6-8+10-12+14}{3-6+9-12+15-18+21}?</cmath>
  13 KB (1,987 words) - 18:53, 10 December 2022
• 2004 AMC 12B Problems
  == Problem 1 == <math>(\mathrm {A}) 3\qquad (\mathrm {B}) 6 \qquad (\mathrm {C}) 9 \qquad (\mathrm {D}) 12 \qquad (\mathrm {E}) 15</mat
  13 KB (2,049 words) - 13:03, 19 February 2020
• 2005 AMC 12B Problems
  == Problem 1 == [[2005 AMC 12B Problems/Problem 1|Solution]]
  12 KB (1,781 words) - 12:38, 14 July 2022
• 2006 AMC 12B Problems/Problem 5
  == Problem == {{AMC12 box|year=2006|ab=B|num-b=4|num-a=6}}
  654 bytes (115 words) - 21:47, 1 August 2020
• 2006 AMC 12B Problems/Problem 7
  == Problem == {{AMC12 box|year=2006|ab=B|num-b=6|num-a=8}}
  1 KB (213 words) - 15:33, 9 April 2024
• 2006 AMC 12B Problems/Problem 9
  == Problem== ...and for each choice there is one acceptable order. Similarly, for <math>c=6</math> and <math>c=8</math> there are, respectively, <math>\binom{5}{2}=10<
  3 KB (409 words) - 17:10, 30 April 2024
• 2006 AMC 12B Problems/Problem 11
  == Problem == Joe has 2 ounces of cream, as stated in the problem.
  927 bytes (137 words) - 10:45, 4 July 2013
• 2006 AMC 12B Problems/Problem 13
  == Problem == ...qrt {3} \qquad \textrm{(C) } 8 \qquad \textrm{(D) } 9 \qquad \textrm{(E) } 6\sqrt {3}</math>
  3 KB (447 words) - 03:49, 16 January 2021
• 2006 AMC 12B Problems/Problem 15
  == Problem == // from amc10 problem series
  3 KB (458 words) - 16:40, 6 October 2019
• 2006 AMC 12B Problems/Problem 16
  == Problem == ...n is <math>\frac{5\sqrt{2}}{2}\cdot\frac{1}{\sqrt{3}}\cdot2 = \frac{5\sqrt{6}}{3}</math>.
  1 KB (203 words) - 16:36, 18 September 2023
• 2006 AMC 12B Problems/Problem 17
  == Problem == ...h>5</math> and <math>6</math> on each die are in the ratio <math>1:2:3:4:5:6</math>. What is the probability of rolling a total of <math>7</math> on the
  1 KB (188 words) - 22:10, 9 June 2016
• 2006 AMC 12B Problems/Problem 19
  == Problem == \mathrm{(A)}\ 4\qquad\mathrm{(B)}\ 5\qquad\mathrm{(C)}\ 6\qquad\mathrm{(D)}\ 7\qquad\mathrm{(E)}\ 8
  4 KB (696 words) - 09:47, 10 August 2015

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