Create the page "Problem 6" on this wiki! See also the search results found.

Page title matches

• 1991 AJHSME Problems/Problem 6
  ==Problem== 10 & 6 & 4 & 3 & 2 \\
  784 bytes (101 words) - 00:06, 5 July 2013
• 1961 AHSME Problems/Problem 6
  == Problem == <math>\textbf{(A)}\ 6\log{2} \qquad
  697 bytes (95 words) - 20:01, 17 May 2018
• 1989 IMO Problems/Problem 6
  ==Problem==
  11 KB (1,928 words) - 12:26, 26 July 2023
• 1999 AHSME Problems/Problem 6
  ==Problem==
  587 bytes (80 words) - 23:59, 16 March 2020
• 2010 AMC 12A Problems/Problem 6
  {{duplicate|[[2010 AMC 12A Problems|2010 AMC 12A #6]] and [[2010 AMC 10A Problems|2010 AMC 10A #9]]}} == Problem ==
  2 KB (320 words) - 04:51, 21 January 2023
• 2007 AMC 8 Problems/Problem 6
  == Problem ==
  764 bytes (115 words) - 12:22, 16 August 2021
• 2010 AIME I Problems/Problem 6
  == Problem == draw(graph(Q,min,max),linetype("6 2")+linewidth(0.7));
  6 KB (1,019 words) - 20:39, 20 November 2023
• 2010 AIME II Problems/Problem 6
  == Problem ==
  2 KB (426 words) - 17:47, 29 June 2022
• 2010 AMC 10B Problems/Problem 6
  ==Problem==
  2 KB (260 words) - 17:00, 1 August 2022
• 2010 USAJMO Problems/Problem 6
  #REDIRECT [[2010 USAMO Problems/Problem 4]]
  43 bytes (4 words) - 06:43, 3 June 2010
• 2010 AMC 12B Problems/Problem 6
  {{duplicate|[[2010 AMC 12B Problems|2010 AMC 12B #6]] and [[2010 AMC 10B Problems|2010 AMC 10B #12]]}} == Problem ==
  1 KB (166 words) - 16:58, 6 July 2023
• 2019 IMO Problems/Problem 6
  ==Problem== [[File:2019 6 s1.png|450px|right]]
  5 KB (792 words) - 01:52, 19 November 2023
• 2010 IMO Problems/Problem 6
  =2010 IMO Problem 6= == Problem ==
  4 KB (786 words) - 08:46, 12 March 2024
• 2010 AMC 10A Problems/Problem 6
  == Problem 6 ==
  1 KB (140 words) - 18:58, 31 August 2022
• 1966 AHSME Problems/Problem 6
  == Problem ==
  1 KB (164 words) - 12:42, 28 January 2020
• 2011 AMC 12A Problems/Problem 6
  == Problem ==
  2 KB (361 words) - 20:39, 21 August 2023
• 2011 AMC 10A Problems/Problem 6
  ==Problem 6== ...<math>B={6, 7, 8, 9, 10, \cdots , 20}</math>. Then, all the integers <math>6</math> through <math>20</math> would be redundant in <math>A \cup B</math>,
  1 KB (160 words) - 20:19, 21 August 2023
• 2021 AIME II Problems/Problem 6
  ==Problem==
  8 KB (1,364 words) - 01:02, 29 January 2024
• 2011 AMC 12B Problems/Problem 6
  == Problem == In order to solve this problem, use of the tangent-tangent intersection theorem (Angle of intersection bet
  2 KB (370 words) - 13:35, 26 January 2021
• 2001 AMC 10 Problems/Problem 6
  ...1 AMC 12 Problems|2001 AMC 12 #2]] and [[2001 AMC 10 Problems|2001 AMC 10 #6]]}} == Problem ==
  1,018 bytes (165 words) - 10:33, 8 November 2021

Page text matches

• 2005 AMC 12B Problems
  == Problem 1 == [[2005 AMC 12B Problems/Problem 1|Solution]]
  12 KB (1,781 words) - 12:38, 14 July 2022
• 2006 AMC 12B Problems/Problem 5
  == Problem == {{AMC12 box|year=2006|ab=B|num-b=4|num-a=6}}
  654 bytes (115 words) - 21:47, 1 August 2020
• 2006 AMC 12B Problems/Problem 7
  == Problem == {{AMC12 box|year=2006|ab=B|num-b=6|num-a=8}}
  1 KB (213 words) - 15:33, 9 April 2024
• 2006 AMC 12B Problems/Problem 9
  == Problem== ...and for each choice there is one acceptable order. Similarly, for <math>c=6</math> and <math>c=8</math> there are, respectively, <math>\binom{5}{2}=10<
  3 KB (409 words) - 17:10, 30 April 2024
• 2006 AMC 12B Problems/Problem 11
  == Problem == Joe has 2 ounces of cream, as stated in the problem.
  927 bytes (137 words) - 10:45, 4 July 2013
• 2006 AMC 12B Problems/Problem 13
  == Problem == ...qrt {3} \qquad \textrm{(C) } 8 \qquad \textrm{(D) } 9 \qquad \textrm{(E) } 6\sqrt {3}</math>
  3 KB (447 words) - 03:49, 16 January 2021
• 2006 AMC 12B Problems/Problem 15
  == Problem == // from amc10 problem series
  3 KB (458 words) - 16:40, 6 October 2019
• 2006 AMC 12B Problems/Problem 16
  == Problem == ...n is <math>\frac{5\sqrt{2}}{2}\cdot\frac{1}{\sqrt{3}}\cdot2 = \frac{5\sqrt{6}}{3}</math>.
  1 KB (203 words) - 16:36, 18 September 2023
• 2006 AMC 12B Problems/Problem 17
  == Problem == ...h>5</math> and <math>6</math> on each die are in the ratio <math>1:2:3:4:5:6</math>. What is the probability of rolling a total of <math>7</math> on the
  1 KB (188 words) - 22:10, 9 June 2016
• 2006 AMC 12B Problems/Problem 19
  == Problem == \mathrm{(A)}\ 4\qquad\mathrm{(B)}\ 5\qquad\mathrm{(C)}\ 6\qquad\mathrm{(D)}\ 7\qquad\mathrm{(E)}\ 8
  4 KB (696 words) - 09:47, 10 August 2015
• 2006 AMC 12B Problems/Problem 21
  == Problem == \mathrm{(D)}\ 6\sqrt {2006}
  2 KB (339 words) - 13:15, 12 July 2015
• 2006 AMC 12B Problems/Problem 23
  == Problem == ...ABC</math>, such that <math>PA=11</math>, <math>PB=7</math>, and <math>PC=6</math>. Legs <math>\overline{AC}</math> and <math>\overline{BC}</math> have
  7 KB (1,169 words) - 14:04, 10 June 2022
• 2006 AMC 12B Problems/Problem 24
  == Problem == \mathrm{(C)}\ \dfrac{\pi^2}{6}
  3 KB (563 words) - 22:45, 24 October 2021
• 2006 AMC 12A Problems\Problem 6
  #REDIRECT [[2006 AMC 12A Problems/Problem 6]]
  45 bytes (5 words) - 14:43, 14 January 2016
• 2006 AMC 12A Problems/Problem 10
  ...ate|[[2006 AMC 12A Problems|2006 AMC 12A #10]] and [[2006 AMC 10A Problems/Problem 10|2006 AMC 10A #10]]}} == Problem ==
  1 KB (167 words) - 23:23, 16 December 2021
• 2006 AMC 12A Problems/Problem 13
  == Problem == <cmath>r_A + r_B + r_C = 6</cmath>
  1 KB (184 words) - 13:57, 19 January 2021
• 2006 AMC 12A Problems/Problem 15
  == Problem == ...{2}\qquad \mathrm{(D) \ } \frac{5\pi}{6} \quad \mathrm{(E) \ } \frac{7\pi}{6}</math>
  919 bytes (138 words) - 12:45, 4 August 2017
• 2006 AMC 12A Problems/Problem 19
  == Problem == ...-axis. The equation of <math>L_1</math> is <math>y=\frac{5}{12}x+\frac{19}{6}</math>, so the coordinate of this point is <math>\left(-\frac{38}{5},0\rig
  2 KB (253 words) - 22:52, 29 December 2021
• 2006 AMC 12A Problems/Problem 20
  ...ate|[[2006 AMC 12A Problems|2006 AMC 12A #20]] and [[2006 AMC 10A Problems/Problem 25|2006 AMC 10A #25]]}} == Problem ==
  5 KB (908 words) - 19:23, 22 September 2022
• 2006 AMC 12A Problems/Problem 22
  == Problem == ...rt{6}+\sqrt{3}\qquad \rm{(D) \ } 3\sqrt{2}+\sqrt{6}\qquad \mathrm{(E) \ } 6\sqrt{2}-\sqrt{3}</math>
  2 KB (343 words) - 15:39, 14 June 2023

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