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  • {{AIME box|year=2000|n=I|num-b=3|num-a=5}} [[Category:Intermediate Geometry Problems]]
    3 KB (485 words) - 00:31, 19 January 2024
  • In the expansion of <math>(ax + b)^{2000},</math> where <math>a</math> and <math>b</math> are [[relatively prime]] p Using the [[binomial theorem]], <math>\binom{2000}{1998} b^{1998}a^2 = \binom{2000}{1997}b^{1997}a^3 \Longrightarrow b=666a</math>.
    679 bytes (98 words) - 00:51, 2 November 2023
  • {{AIME box|year=2000|n=I|num-b=1|num-a=3}} [[Category:Intermediate Geometry Problems]]
    3 KB (434 words) - 22:43, 16 May 2021
  • {{AIME box|year=2000|n=I|before=First Question|num-a=2}} [[Category:Introductory Number Theory Problems]]
    1 KB (163 words) - 17:44, 16 December 2020
  • ...> in base <math>10</math>, it must be equal to <math>2A</math>, so <math>B<2000</math> when <math>B</math> is looked at in base <math>10.</math> If <math>B</math> in base <math>10</math> is less than <math>2000</math>, then <math>B</math> as a number in base <math>7</math> must be less
    3 KB (502 words) - 11:28, 9 December 2023
  • ...{2001}+-x^{2001}=0</math>, so the term with the largest degree is <math>x^{2000}</math>. So we need the coefficient of that term, as well as the coefficien ...{2001}{1} \cdot (-x)^{2000} \cdot \left(\frac{1}{2}\right)^1&=\frac{2001x^{2000}}{2}\\
    2 KB (335 words) - 18:38, 9 February 2023
  • ...begin{align*}\frac{ax+2001}{a+1}-40=\frac{ax+1}{a+1} \Longrightarrow \frac{2000}{a+1}=40 \Longrightarrow a=49\end{align*}</cmath> {{AIME box|year=2001|n=I|num-b=1|num-a=3}}
    1 KB (225 words) - 07:57, 4 November 2022
  • {{AIME box|year=2000|n=II|num-b=14|after=Last Question}} [[Category:Intermediate Trigonometry Problems]]
    3 KB (469 words) - 21:14, 7 July 2022
  • ...s the factorial base expansion of <math>16!-32!+48!-64!+\cdots+1968!-1984!+2000!</math>, find the value of <math>f_1-f_2+f_3-f_4+\cdots+(-1)^{j+1}f_j</math 16!-32!+48!-64!+\cdots+1968!-1984!+2000!&=16!+(48!-32!)+(80!-64!)\cdots+(2000!-1984!)\\
    7 KB (1,131 words) - 14:49, 6 April 2023
  • {{AIME box|year=2000|n=II|num-b=12|num-a=14}} [[Category:Intermediate Algebra Problems]]
    6 KB (1,060 words) - 17:36, 26 April 2024
  • {{AIME box|year=2000|n=II|num-b=11|num-a=13}} [[Category:Intermediate Geometry Problems]]
    3 KB (532 words) - 13:14, 22 August 2020
  • {{AIME box|year=2000|n=II|num-b=10|num-a=12}} [[Category:Intermediate Geometry Problems]]
    4 KB (750 words) - 22:55, 5 February 2024
  • {{AIME box|year=2000|n=II|num-b=9|num-a=11}} [[Category:Intermediate Geometry Problems]]
    2 KB (399 words) - 17:37, 2 January 2024
  • ...th>, find the least integer that is greater than <math>z^{2000}+\frac 1{z^{2000}}</math>. Using [[De Moivre's Theorem]] we have <math>z^{2000} = \cos 6000^\circ + i\sin 6000^\circ</math>, <math>6000 = 16(360) + 240</m
    4 KB (675 words) - 13:42, 4 April 2024
  • {{AIME box|year=2000|n=II|num-b=7|num-a=9}} [[Category:Intermediate Geometry Problems]]
    4 KB (584 words) - 19:35, 7 December 2019
  • {{AIME box|year=2000|n=II|num-b=6|num-a=8}} [[Category:Intermediate Combinatorics Problems]]
    2 KB (281 words) - 12:09, 5 April 2024
  • {{AIME box|year=2000|n=II|num-b=5|num-a=7}} [[Category:Intermediate Geometry Problems]]
    3 KB (433 words) - 19:42, 20 December 2021
  • {{AIME box|year=2000|n=II|num-b=4|num-a=6}} [[Category:Intermediate Combinatorics Problems]]
    1 KB (184 words) - 21:13, 12 September 2020
  • {{AIME box|year=2000|n=II|num-b=3|num-a=5}} [[Category:Intermediate Number Theory Problems]]
    2 KB (397 words) - 15:55, 11 May 2022
  • {{AIME box|year=2000|n=II|num-b=2|num-a=4}} [[Category:Intermediate Combinatorics Problems]]
    1 KB (191 words) - 04:27, 4 November 2022

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